Answer:
1,2,5
Step-by-step explanation:
Answer:
12g+13 can I have brain lest...
An x-intercept is the point where the function passes the x axis at y=0.
The y-intercept is the point where the function crosses the y axis at x=0
1. It is an x-intercept, so y = 0. The ordered pair would be (-6, 0)
2. It is a y-intercept, so x = 0. The ordered pair would be (0, -2.3)
3. It is a y-intercept, so x=0. The ordered pair would be (0, 3/4)
To find the x-intercept, set y = 0. To find the y-intercept, set x=0
4. y-intercept: y = 3(0) -9. y = -9 The y-intercept is at (0, -9)
x-intercept: 0 = 3x -9. 9 = 3x. x = 3. The x-intercept is at (3, 0)
5. x intercept: 0 = 5x +10. -10 = 5x. x = -2. The x-intercept is at (-2, 0)
y-intercept: y = 5(0) + 10. y = 10. The y-intercept is at (0, 10)
If you look at finding the y-intercepts in the two problems above, you may see there is a pattern forming. The y-intercept is the number that your adding or subtracting that is located after the x (ex. y = 4x - 2 - the y-intercept would be -2)
9. First, find the x and y-intercepts. The y intercept is -3 You’d graph that at (0, -3). 0 = -1/2x - 3. -1/2x = 3. x = -6 so the x-intercept is at (-6, 0). If you only need to graph 2 points, then you can graph just those two points and draw a line between them.
To graph y=-1/2x + 3, start at the y-intercept and use the slope (-1/2) to find other points. Because your slope is -1/2, you’d go down 1 unit and then to the right 2 units. That would be your next point. If you wanted your line to go further up, go up one unit and then to the left 2 units. That would be your next point.
I am not sure what you need to do on 11 and 12
I think you should try 7, 8 and 10 on your own and let me know if you have any questions on them or if you are stuck on anything.
1. 51
2. 34
3. 95
4. 38
5. 47
6. 74
7. 59
I hope this helps!!
Answer:
a) f(x) = x^2
b) f(x) = x
c) any pair of numbers
Step-by-step explanation:
HI!
a)
an example of this kind of function is f(x) = x^2 because
f(x+h) = (x+h)^2 = x^2 + h^2 + 2 xh = f(x) + f(h) + 2xh
teherfore
f(x+h) ≠ f(x) + f(h)
other example is f(x) = x^n with n a whole number different than one
e.g.
f(x)=x^3
f(x+h) = (x+h)^3 = x^3 + h^3 + 3(x^2 h + x h^2) ≠ x^3 + h^3 = f(x) + f(h)
b)
f(x) = x is a function that actually behaves as indicated
f(x+h) = x + h = f(x) + f(h)
others examples of this kind of fucntion are given by multiplying x by any number:
f(x) = ax; f(x+h) = a(x+h) = ax + ah = f(x) + f(h)
c)
Any pair of numbers will make f(x+h) = f(x) + f(h), as mentioned in the previous section
lest consider 10 and 5
f(10+5) = 2 *(10+5) = 2*15 = 30
f(10) = 2*10 = 20
f(5) = 2*5 = 10
f(10) + f(5) = 20+10 = 30 = f(10+5)
