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s344n2d4d5 [400]
3 years ago
11

Find the mean absolute deviation of the following numbers: 53, 39, 40, 42, 36, 58, 49, 55, 44, 51. i need help

Mathematics
2 answers:
Darya [45]3 years ago
8 0

add the numbers together 53, 39, 40, 42, 36, 58, 49, 55, 44, 51 = 467

then 467 divided 10 ( because there is 10 numbers together ) = 46.7

Neko [114]3 years ago
6 0

\left|\dfrac{53+39+40+42+36+58+49+55+44+51}{10}\right|\\\\=\left|\dfrac{467}{10}\right|=|46.7|=46.7

Answer: 46.7

MAD:

first you add up all the values, next you divide by the number of values.

If the number results as a negitave number, use the absolute value.


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The slope of a tangent line in the polar coordinate is given by:

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Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

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θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

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</span>θ = <span>4.91718592528713</span>
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