9514 1404 393
Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
![f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)](https://tex.z-dn.net/?f=f%28t%29%3D%5Csqrt%5B3%5D%7Bt%7D%2820-t%29%5C%5C%5C%5Cf%27%28t%29%3D%5Cdfrac%7B20-t%7D%7B3%5Csqrt%5B3%5D%7Bt%5E2%7D%7D-%5Csqrt%5B3%5D%7Bt%7D%3D%5Csqrt%5B3%5D%7Bt%7D%5Cleft%28%5Cdfrac%7B4%285-t%29%7D%7B3t%7D%5Cright%29)
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
Answer:
60 miles per hour
Step-by-step explanation:
For each point just divide the miles by the hour
120/2 = 60 mph
180/3 = 60 mph
240/4 = 60 mph
Answer:
"6 out of 10 people" means the ratio of class:no_class is 6:4
990/10 = 99, the smallest the "class" and the "no_class" add up to is 10. And, generally, the total divides with that nicely, as in this case.
99(6) = 594 ----------- probably class
99(4) = 396 ------------------ probably no class
Total = 990
I hope this helps
Step-by-step explanation:
BRAINLIEST?
The solution is D.
By plugging the x value, 5, into the equation:
6*5=30
30+1=31
y=31
the x value is 5 and the y value is 31
(5, 31)
hope that helps!
