Answer:
Alleles for feather colour exhibit incomplete dominance or co-dominance.
50% gray offspring + 50% black offspring
Explanation:
<em>It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.</em>
Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.
Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.
15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.
Bb x Bb = 1BB, 2Bb, and 1bb
Crossing the gray rooster (Bb) with a black hen (bb):
Bb x bb = Bb, Bb, bb, and bb
= 2Bb (gray):2bb (black)
50% of the offspring will be gray while the remaining 50% will be black.
Answer:
D
dont forget brainliest :)
I’m pretty sure it’s your veins
<span>Answer:
Medical caretakers utilize the SBAR procedure to report brief, correlated, and finish verbal data when speaking with doctors, taking part in handoffs, and offering attendant to-nurture move reports. Nursing reports and handoffs should be performed proficiently on the grounds that they give us the chance to make inquiries, look for illumination, and affirm data.
SBAR can be particularly significant when we're required to report a basic circumstance to doctors in which successful correspondence is imperative to the patient's clinical results and wellbeing. The primary goal of utilizing SBAR is to verbalize a rising condition and get arrangement situated criticism.</span>
