Hello!
Ok so for this problem we use the ideal gas law of PV=nRT and I take it that the scientist needs to store 0.400 moles of gas and not miles.
So if we have
n=0.400mol
V=0.200L
T= 23degC= 273k+23c=296k
R=ideal gas constant= 0.0821 L*atm/mol*k
So now we rearrange equation for pressure(P)
P=nRT/V
P=((0.400mol)*(0.0821 L*atm/mol*k)*(296k))/(0.200L) = 48.6 atm of pressure
Hope this helps you understand the concept and how to solve yourself in the future!! Any questions, please feel free to ask!! Thank you kindly!!!
If my memory serves me well, the correct answer is: Chemical processes store and release <span>C: energy</span><span> in the bonds of molecules.
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Answer:
The correct option is C ( the activation energy is lowered, the reactant molecules collide more frequently and with greater energy per collision).
Explanation:
The rate of a chemical reaction is defined as the quantity of products that are formed per unit time. Rates can be computed based on either how the reactants are used up or how products are formed.
There are factors that affects the rate of a chemical reaction and they include TEMPERATURE, catalyst, surface area of reacting substances and many among others.
TEMPERATURE increase in most chemical reactions increases the rate of the reaction. This is because molecules gain more energy at higher temperatures. This increases their kinetic energy resulting in more effective collision of the reactant molecules. The rate of reaction depends on the frequency of this effective collisions between the reacting particles.
Effective collision are those that result in reactions, which when they occur, the colliding particles become activated with increased kinetic energy. This kinetic energy must exceed a particular energy barrier for a particular reaction if the reaction must take place. This energy barrier that must be overcome is known as the ACTIVATION ENERGY.
Answer:
3,32e-14 moles
Explanation:
We use the number of Avogadro:
6,02e23 molecules-------1 mol
2e10molecules------------X =2e10/6,02e23= 3,32x-14 moles
Answer & Explanation:
Kindly find the attached presentation.
