1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eduardwww [97]
3 years ago
11

In this experiment, we will be performing a titration with a buret. place the steps in order. 1. record the ph when 0.0 ml of na

oh has been added to your beaker containing 25 ml of hcl and 25 ml of deionized water. 2. record the ph of your partially neutralized hcl solution when 5.00 ml of naoh has been added from the buret. 3. record the ph of your partially neutralized hcl solution when 10.00ml, 15.00ml and 20.00ml of naoh has been added. 4. record the ph of your partially neutralized hcl solution when 21.00 ml, 22.00 ml, 23.00 ml and 24.00 ml of naoh has been added. 5. add naoh one drop at a time until a ph of 7.00 has been reached, then record the volume of naoh added from the buret. 6. record the ph of your basic hcl-naoh solution when 26.00 ml, 27.00 ml, 28.00 ml, 29.00 ml and 30.00 ml of naoh has been added. 7. record the ph of your basic hcl-naoh solution when 35.00 ml, 40.00 ml, 45.00ml and 50.00 ml of naoh has been added from your 50ml buret.
Chemistry
1 answer:
77julia77 [94]3 years ago
4 0

I am guessing that your solutions of HCl and of NaOH have approximately the same concentrations. Then the equivalence point will occur at pH 7 near 25 mL NaOH.

The steps are already in the correct order.

1. Record the pH when you have added 0 mL of NaOH to your beaker containing 25 mL of HCl and 25 mL of deionized water.

2. Record the pH of your partially neutralized HCl solution when you have added 5.00 mL of NaOH from the buret.

3. Record the pH of your partially neutralized HCl solution when you have added 10.00 mL, 15.00 mL and 20.00 mL of NaOH.

4. Record the NaOH of your partially neutralized HCl solution when you have added 21.00 mL, 22.00 mL, 23.00 mL and 24.00 mL of NaOH.

5. Add NaOH one drop at a time until you reach a pH of 7.00, then record the volume of NaOH added from the buret ( at about 25 mL).

6. Record the pH of your basic HCl-NaOH solution when you have added 26.00 mL, 27.00 mL, 28.00 mL, 29.00 mL and 30.00 mL of NaOH.

7. Record the pH of your basic HCl-NaOH solution when you have added 35.00 mL, 40.00 mL, 45.00 mL and 50.00 mL of NaOH from your 50mL buret.

You might be interested in
What is the proper name for MgSO4 7H2O?
lukranit [14]
A. magnesium sulfate heptahydrate 
that is what it stands for 
7 0
4 years ago
Read 2 more answers
When adding sugar to tea, it was observed that the sugar kept dissolving. After a
a_sh-v [17]

The molecule of  mixture  cannot be seen hence, it will be considered as homogeneous mixture.

<h3>What is molecule?</h3>

A molecule is just a collection of more than two atoms bound together by chemical bonds; depending on the context, the phrase doesn't have to include ions that meet this requirement.

<h3>What is homogeneous mixture?</h3>

Solids, liquids, as well as gases, can all be homogeneous mixtures. Through, they have almost the same look and chemical makeup.

When sugar will be dissolved, the sucrose molecules get separated from one another. The materials that make up individual molecules stay together like sucrose molecules sucrose molecules, so the molecule will not break up.

Therefore mixture can be considered as molecule and homogeneous mixture.

brainly.com/question/9192462

#SPJ2

6 0
2 years ago
Read 2 more answers
Determine the change in entropy for 2.7 moles of an ideal gas originally placed in a container with a volume of 4.0 L when the c
olchik [2.2K]

Answer:

The value of entropy change for the process dS = 0.009 \frac{KJ}{K}

Explanation:

Mass of the ideal gas = 0.0027 kilo mol

Initial volume V_{1} = 4 L

Final volume V_{2} = 6 L

Gas constant for this ideal gas ( R ) = R_{u}  M

Where R_{u} = Universal gas constant = 8.314 \frac{KJ}{Kmol K}

⇒ Gas constant R = 8.314 × 0.0027 = 0.0224 \frac{KJ}{K}

Entropy change at constant temperature is given by,

dS = R  log _{e} \frac{V_{2}}{V_{1}}

Put all the values in above formula we get,

dS = 0.0224  log _{e} [\frac{6}{4}]

dS = 0.009 \frac{KJ}{K}

This is the value of entropy change for the process.

6 0
3 years ago
Rain is-pouring down on you. Your friend asks where so much water
Aleks04 [339]

Answer:

D

Explanation:

It could come from anybody of water around you that had some water evaporated.

4 0
2 years ago
Read 2 more answers
I NEED HELP FAST!!!!! Can you tell me about factors that change matter from one state to another??? I have a DBA in a few minute
EleoNora [17]
Adding energy to a matter causes a physical change. Head to water becomes vapor--taking energy away also causes physical change, (water becoming ice,) when heat is the energy being removed. 
8 0
3 years ago
Read 2 more answers
Other questions:
  • Uranium-238 decays very slowly.its half-life is 4.47 billion years.
    7·2 answers
  • PLEASE ANSWER
    9·1 answer
  • What is the total number of protons in the nucleus of an atom of potassium-42?
    10·1 answer
  • Which is equal to 7 hectometers?
    8·2 answers
  • The oxidation of glucose can result in several products. You perform combustion analysis on a 2.750 g sample that resulted from
    5·1 answer
  • As two objects that are oppositely charged are brought together which will happen
    5·1 answer
  • Oxidation and reduction reactions (redox) involve the loss and gain of electrons. Half-reactions are a way for us to keep track
    12·1 answer
  • Which of the following is NOT
    5·1 answer
  • What is chromatography​
    15·2 answers
  • The atomic weight of an atom is the sum of the mass of the particles in the nucleus of the atom. These particles are called?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!