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Blizzard [7]
4 years ago
13

The radiative zone is the outer shell of the sun from which light energy is radiated. True False

Chemistry
2 answers:
Mumz [18]4 years ago
8 0
The Sun's radiative zone is the section of the solar<span> interior between the innermost core and the outer </span>convective<span> zone therefore it is false</span>
stiks02 [169]4 years ago
4 0

<u>Answer: </u>The correct answer is False.

<u>Explanation:</u>

Sun consists of three zones: The core, Radiative zone and the Convective Zone.

Core is the inner most part of the Sun. The temperature of this zone is around 15 million Kelvin.

Radiative zone is the zone which lies between the core and the outer layer known as convective zone. the temperature of this zone is around 7 million Kelvin to 2 million Kelvin.

Convective zone is the zone which lies in the outer shell of the Sun and through which light energy is radiated in the space. The temperature of this zone is around 2 million Kelvin to 5800 Kelvin.

Hence, the correct answer is False.

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Which of the following statements is TRUE?
blagie [28]

Answer:

the correct answer is E

Explanation:

None of the options is correct, because entropy is the thermodynamic magnitude that indicates the degree of molecular disorder of a system, in exothermic processes energy or heat is released to the medium and energy is taken from the medium in endothermic processes, entropy if it depends of the temperature since the temperature is what sometimes determines if the process is spontaneous or not, and the delta universe in spontaneous processes is not always greater than zero, it is more frequently less than zero with negative values.

7 0
3 years ago
Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.660 V when (Zn^2+)=0.22 M and(
yaroslaw [1]

Answer:

pH = 2.059

Explanation:

At the Cathode:

The reduction reaction is:

2H^+ + 2e^- \to H_2   \ \ \ \mathbf{E^0_{red}= 0.00 \ V}

At the anode:

At oxidation reaction is:

Zn \to Zn^{2+} +2e^-   \ \ \ \mathbf{E^0_{ox} = 0.76 \ V}

The overall equation for the reaction is:

\mathbf{Zn + 2H^+ \to Zn^{2+} + H_2}

The overall cell potential is:

\mathbf{E^0_{cell}= E^0_{ox} + E^0_{red}}

\mathbf{E^0_{cell}= 0.76 \ V +0.00 \ V}

\mathbf{E^0_{cell}= 0.76\ V}

Using the formula for the Nernst equation:

E = E^0 - ( \dfrac{0.0591}{n})log (Q)\\

where;

E = 0.66

(Zn^2+)=0.22 M

Then

0.66 =0.76- ( \dfrac{0.0591}{2})log \bigg ( \dfrac{[Zn^{2+} ] PH_2}{[H^+]^2} \bigg )

0.66 =0.76- 0.02955 * log \bigg ( \dfrac{0.22*0.87}{[H^+]^2} \bigg )

3.4 = log ( 0.1914) - 2 log [H⁺]

3.4 = -0.7180 - 2 log [H⁺]

3.4 + 0.7180 = - 2 log  [H⁺]

4.118  = - 2  log  [H⁺]

pH = log [H⁺] = 4.118/2

pH = 2.059

8 0
3 years ago
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serg [7]

Answer:

ITS B

Explanation:

MY CONSCIOUS MIND IS TELLING ME

6 0
2 years ago
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4vir4ik [10]

What does botanist study?

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