Answer: (-3,4) and (9,20)
I think these two points will make the answer you have been looking for.
Line segment of length k is divided into 3 equal parts.
so first segment is 0-k/3 and third segment is 2/3k-k
so mid-pt of 1st = k/6 and 3rd = 5/6k
so the distance in between = 5/6k-k/6 = 4/6k = 2/3k
Answer:
Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .
Step-by-step explanation:
We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;
Mean, 
= 1.3 cm and Standard deviation, 
= 0.01 cm
Also, since distribution is normal;
Z = 
~ N(0,1)
Let X = range of diameters
So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)
P(X < 1.33) = P( < 
) = P(Z < 3) = 0.99865
P(X <= 1.27) = P( < 
) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865
= 0.00135
P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .
Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .
84
Step-by-step explanation:
All three angles add up to 180 degrees.
Since it is a right triangle, there is a 90 degrees angle. And we know another angle is 6 degree. So we use the formula: 180 - (known angle + known angle) = unknown angle
Plugging in the information we get: 180 - (90 + 6) = x
180 - 96 = 84
So x = 84
We can check our work by adding all known angles to see if it is equal to 180 using the formula known angle + known angle + known angle = 180 degrees
Plugging in the information we get: 90 + 6 + 84 = 180
96 + 84 = 180
180 = 180
So the answer 84 is correct
