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lorasvet [3.4K]

2 years ago

12

The baker pays $0.80 per pound for sugar and $1.25 per pound for butter. Which of the following equations shows t, how much the

baker will spend if he buys 6 pounds of butter and 20 pounds of sugar?

2 answers:

Lynna [10]2 years ago

5 0

Answer:

(6 x $1.25) + (20 x $0.80)

lana66690 [7]2 years ago

3 0

Answer:

23.5

Step-by-step explanation:

1. multiply 1.25 by 6

2. multiply 0.80 by 20

3. add both answers

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3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

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2 years ago

HEEELLLPPP!!!!!!!!! PLEEAASEEE!!!!!!!!

Ksivusya [100]

Answer:

Step-by-step explanation:

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$19. \dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{(-7p^{4})*(-8p^{5})}{2p^{3}}= \dfrac{(-7)*(-8)*p^{4}*p^{5}}{2p^{3}}\\\\\\=(-7)*(-4)*p^{4+5-3} \\\\= 28p^{6}\\$

$20)\dfrac{15a^{16}b^{11}}{(3a^{4}b^{2})^{3}}=\dfrac{15a^{16}b^{11}}{3^{3}*a^{4*3}*b^{2*3}}\\\\\\=\dfrac{15a^{16}b^{11}}{27*a^{12}*b^{6}}\\\\=\dfrac{5*a^{16-12}*b^{11-6}}{9}\\\\\\=\dfrac{5a^{4}b^{5}}{9}$

4 0

1 year ago

Ok so I have 40 and I need to make it into a mixed fraction

slava [35]

Your Answer Is 40 It’s Simple Really If You Kinda Think About It But Has A Fraction It Would Be 40/1

8 0

3 years ago

Evaluate the expression when g=3 and h= 39.<br> h-69<br> L<br> B.<br> X6<br> ?

lawyer [7]

Answer:
39-18 is 21.
Explanation:

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2 years ago

A recipe for lemonade requires 10 parts of water to every 6 parts of lemon juice. How many cups of water should be added to 30 c

Nookie1986 [14]

Answer:

50

Step-by-step explanation:

10=6

?=30

5 0

2 years ago

Read 2 more answers