F=kq'q"/d²
charge of electron(q')= 1.6022*10^-19
charge of proton (q")= -1.6022*10^-19
Coulomb's constant (k)= 9*10^9
distance (d)=10^-10
substituting values into equation
F= (9*10^9)*(1.6022*10^-19)(-1.6022*10^-19)/(10^10)²
F= -2.31034036 × 10^-48N
Answer:continuous electric current
Explanation:
Directionally proportional
To trigger a drug-dog alert, the
necessary threshold level would be around 1 to 10 micrograms of methyl
benzoate.
In the 1999 Furton study, it was
stated that it would take 500 milligrams of cocaine in order to emit 1 to 10
micrograms of Methyl Benzoate.
A colorless liquid that is poorly soluble in water is one of
the properties of <span>methyl benzoate.</span>
The dehydration of cyclopentanol is shown in the balanced equation below:
Cyclopentanol => cyclopentene + H2O
Therefore, the alkene produced from the dehydration of cyclopentanol is cyclopentene.
The OH group is removed from the compound resulting to an alkene, cyclopentene. <span />
