What is a necessary reactant for glycolytic, or anaerobic, catabolism to proceed?

1 answer:

6 0

For glycolysis or an anaerobic catabolism to proceed, GLUCOSE must be present. It is the main reactant of the processes and it is broken down to form pyruvate, which is subsequently converted into energy, in the form of ATP molecules. One glucose is converted into two pyruvate molecules, in which 2 ATP are consumed, and 4 are generated.

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Ammonia is an important ingredient in many fertilizers. The main process by which ammonia is made is the Haber process. In this

Basile [38]

"High temperatures make the gas molecules move more quickly" is the one sentence among all the choices given in the question that most likely explains why this reaction is carried out at high temperature. The correct option among all the options that are given in the question is the third option or option "C".

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3 years ago

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U-238 has _____ protons and 146 neutrons

qaws [65]

U-238
The number besides the U means its total molar mass. The molar mass of this element is 238
Molar mass= protons + neutrons
This means that 238= 146 + protons
Do 238 - 146
Answer is 92

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2 years ago

Boron sulfide, B2S3(s), reacts violently with water to form dissolved boric acid (H3BO3) and hydrogen sulfide gas

Gwar [14]

The equation structure for the above mentioned reaction can be written as

$B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow$

<u>Explanation:</u>

Considering the above reaction, When Boron sulfide, reacts with water more violently to form boric acid and hydrogen sulfide gas.

$B_{2} S_{3}+H_{2} O \rightarrow H_{3} B O_{3}+H_{2} S \uparrow$

In order to balance the equation, we can do as follows.There are 2 B - atoms on both sides of the equation, but only 2 H - atoms, and one O - atom on LHS, so we have to balance it by putting 6 in front of water and 2 in front of Boric acid and 3 in front of hydrogen sulphide gas, so that we have 2 B - atoms, 3 - S atoms, 12 H - atoms on both sides of the equation, and it is balanced. Balanced equation is given as,

$B_{2} S_{3}+6 H_{2} O \rightarrow 2 H_{3} B O_{3}+3 H_{2} S \uparrow$

Thus a Balanced equation of the above mentioned reaction is written.

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How many moles are in 4561 g of C3H7OH?

d1i1m1o1n [39]

Answer: 76.017 moles

Explanation:

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mars1129 [50]

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