Answer:
The component of orthogonal to is .
Step-by-step explanation:
Let and , from Linear Algebra we get that component of parallel to by using this formula:
(Eq. 1)
Where is the norm of , which is equal to . (Eq. 2)
If we know that and , then we get that vector component of parallel to is:
Lastly, we find the vector component of orthogonal to by applying this vector sum identity:
(Eq. 3)
If we get that and , the vector component of is:
D. 6x2^2y^2 + 10xy^2 - 2x^2y^3
Pythagoras theorem I guess
I believe its 17, this is a 90 degree angle, so 90-73=17