2 years ago

The percent of a discount is 75% and the sale price is $55.50 what is the original price?

Mathematics

1 answer:

nikitadnepr [17]2 years ago

4 0

Answer:

Step-by-step explanation:

55.50/75 = 1% of original price=0.74

0.74*100= original price before sale= $74

You might be interested in

What statement about a rhombus is never true?

Alekssandra [29.7K]

It can never be a square.

7 0

3 years ago

Read 2 more answers

Find x to the nearest hundredth.

Karolina [17]

Answer:

23.78

Step-by-step explanation:

CAH

x/25

cos18=x/25

25cos18=x

x=23.78

5 0

3 years ago

Read 2 more answers

Identify the graphed linear equation.

Marrrta [24]

C
step by step explanation:

8 0

2 years ago

Question

Zolol [24]

D. The last one because slope is -99 which is decresed

5 0

1 year ago

8x2 − 5 + 7x4 − 9x − x5

Veseljchak [2.6K]

Answer:

$=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

Step-by-step explanation:

Factor out comon Term -1

$=-\left(x^5-7x^4-8x^2+9x+5\right)$

Factor $x^5-7x^4-8x^2+9x+5:\quad \left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

$x^5-7x^4-8x^2+9x+5$

Use the rational root theorem

$a_0=5,\:\quad a_n=1$

The dividers of $a_{0}$ : 1, 5, The dividers of $a_n$ : 1

Therefore, check the following rational numbers: ± $\frac{1,\:5}{1}$

$\frac{1}{1}$ is a root of the expression, so factor out $x-1$

$=\left(x-1\right)\frac{x^5-7x^4-8x^2+9x+5}{x-1}$

$\frac{x^5-7x^4-8x^2+9x+5}{x-1}=x^4-6x^3-6x^2-14x-5$

$=x^4-6x^3-6x^2-14x-5$

$=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

8 0

3 years ago