All categories

3 years ago

Which of the following is an obstacle to creating computer-based models for tracking a hurricane?

2 answers:

5 0

Forecasters must consider a large number of variables that affect the path of the storm.
This makes it difficult to create computer-based models because all of these variables are hard to incorporate.

Nookie1986 [14]3 years ago

5 0

Answer:

<h2>Forecasters must consider a large number of variables that affect the path of the storm.</h2>

Explanation:

Btw this is the correct answer, and the other person that said this answer got a low rating...they got it right though.

You might be interested in

Truck drivers probably cannot see your vehicle if____.

laiz [17]

Answer Is Tailgating

6 0

3 years ago

Timbre describes the sound’s _____. pitch loudness tone quality

Bumek [7]

Answer:

A) pitch

Explanation:

I did band and also g*ogled it to check :)

If it isn't A, however, it is C

Hope this helps :D

7 0

2 years ago

Read 2 more answers

A -3.00 nc point charge is at the origin, and a second -5.50 nc point charge is on the x-axis at x = 0.800 m. find the electric

Liula [17]

The electric field produced by a single-point charge is given by

$E(r)=k\frac{q}{r^2}$

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

To find the electric field at x=0.200 m, we need to find the electric field produced by each charge at that point, and then find their resultant.

1) The first charge is $q=-3.00 nC=-3.00 \cdot 10^{-9} C$ , and it is located at x=0, so its distance from the point x=0.200 m is

$r=0.200 m-0=0.2 m$

Therefore, the electric field is

$E_1=(8.99 \cdot 10^9 Nm^2C^{-2})\frac{(3.0 \cdot 10^{-9} C)}{(0.2 m)^2}=675 N/C$

And since the charge is negative, the direction of the field is toward the charge, so toward negative x direction.

2) The second charge is $q=-5.50 nC=-5.5 \cdot 10^{-9}C$ and it is located at x=0.800 m, so its distance from the point is

$r=0.800 m-0.200 m=0.6 m$

Therefore, the electric field is

$E_2 = (8.99 \cdot 10^9 Nm^2C^{-2})\frac{(5.5 \cdot 10^{-9} C)}{(0.6 m)^2}=137.5 N$

And since the charge is negative, the direction of the field is toward the charge, so toward positive x-direction.

3) The total electric field at x=0.200 m will be given by the difference between the two fields (because they are in opposite directions). Taking the x-positive direction as positive direction, we have

$E=E_2 -E_1 =137.5 N/C/C-675 N/C=-537.5 N/C$

and the sign tells us that the field is directed toward negative x-direction.

7 0

3 years ago

A 55.0-g piece of copper wire is heated, and the temperature of the wire changes from 19.0°C to 86.0°C. The amount of heat absor

Alinara [238K]

The specific heat of a metal or any element or compound can be determined using the formula Cp = delta H / delta T / mass. delta pertains to change. That is change in enthalpy and change in temperature. From the given data, Cp is equal to 343 cal per (86-19) c per 55 grams. This is equal to 0.093 cal / g deg. Celsius

4 0

3 years ago

Amplitude and energy are inversely related, meaning that a high-energy wave has low amplitude and a low-energy wave has high amp

Elodia [21]

According to the physical fact that amplitude and energy have proportional values, this statement is definitely FALSE. Pay attention on the words '' inversely related'', that will be the main point which will make it absolutely clear. Hope you will find this answer helpful! Regards.

8 0

3 years ago