ASAP PLS

Mathematics

2 answers:

Wittaler [7]3 years ago

8 0

Assuming Earth's gravity, the formula for the flight of the particle is:

s(t) = -16t^2 + vt + s = -16t^2 + 144t + 160.

This has a maximum when t = -b/(2a) = -144/[2(-16)] = -144/(-32) = 9/2.

Therefore, the maximum height is s(9/2) = -16(9/2)^2 + 144(9/2) + 160 = 484 feet.

Diano4ka-milaya [45]3 years ago

7 0

Answer:

484

Step-by-step explanation:

test=right

You might be interested in

A pelican is flying 17 feet above sea level. Directly below the bird is a trout that is swimming 23 feet below

Nadusha1986 [10]

A
Because if you do the math

4 0

2 years ago

Which equation is true? I. (32 ÷ 8 – 2)6 = (32 – 1)2 II. 72 ÷ 9·4 = 62 ÷ (6 + 3) II only Neither I nor II I only I and II

Umnica [9.8K]

Answer: The answer is (b) Neither I nor II.

Step-by-step explanation: We are given two equations and we need to find which is true. Since it is a simple algebraic question, so we just need to follow BODMAS rule to check the equations.

The equations are as follows -

$(I)~~L.H.S=(\dfrac{32}{8}-2)6=(4-2)6=2\times 6=12.$

$R.H.S=(32-1)2=31\times 2=62.$

Since L.H.S ≠ R.H.S, so this equation is not correct.

$(II)~~L.H.S=\dfrac{72}{9\times 4}=2.$

$R.H.S=\dfrac{62}{6+3}=\dfrac{62}{9}.$

Since L.H.S ≠ R.H.S, so this equation is also not correct.

Thus, the correct option is (b) Neither I nor II.

4 0

2 years ago

Read 2 more answers

A rectangle has a height of 2x^4 with a width of x^2+8x+15. Express the area of the rectangle.

Amiraneli [1.4K]

Hi there!

We know that the formula for the area of a rectangle is height * width. Thus, we can multiply these two expressions together:

$2x^4\cdot (x^2+8x+15)\\$

Now, we know through the distributive property that we can distribute the $2x^4\\$ to everything in the parenthesis. Once this is done, we get:

$2x^4 \cdot x^2+2x^4\cdot8x+2x^4\cdot15$

Now, we know through the power rule that when two exponents are multiplied together with the same base, the exponent can be added together $(x^a \cdot x^b = x^{a+b})$ . This then would make our equation: