All categories

3 years ago

What happens along a stationary front?

Physics

1 answer:

oee [108]3 years ago

3 0

Answer: b. The flow of air is neither toward the warm air mass nor toward the cold air mass.

A stationary front forms between two air masses. A stationary front results when the warm front or cold front air stops moving. This occurs due to the fact that warm front and cold front air masses being opposite to each other but neither of them are able to repel the other. This affects the climatic conditions of the region. The weather is often cloudy along a stationary front and also supported with fall of rain and snow especially if the air in the front is cold with low atmospheric pressure.

Therefore, along a stationary front the flow of air is neither toward the warm air mass nor toward the cold air mass.

You might be interested in

The magnetic fields repel each other when both poles are the same because...

nadezda [96]

A b c d etc. oh well
Are there any choices perhaps? Gracie

5 0

3 years ago

Read 2 more answers

The specific heat of soil is 0.20 kcal/kg*C and the specific heat of water is 1.00 kcal/kg*C. This means that if 1 kg of soil an

stiv31 [10]

Answer: The soil will be $4\°C$ warmer than the water.

Explanation:

The heat (thermal energy) absorbed can be found using the following equation:

$Q=m.C.\Delta T$

Where:

$Q$ is the heat

$m$ is the mass of the element

$C$ is the specific heat capacity of the material.

$\Delta T$ is the variation in temperature

In the case of soil we have:

$Q_{soil}=m_{soil}.C_{soil}.\Delta T_{soil}$ (1)

Where:

$Q_{soil}=1 kcal$

$m_{soil}=1 kg$

$C_{soil}=0.2 kcal/kg \°C$

$\Delta T_{soil}$

In the case of water we have:

$Q_{water}=m_{water}.C_{water}.\Delta T_{water}$ (2)

Where:

$Q_{water}=1 kcal$

$m_{water}=1 kg$

$C_{water}=1 kcal/kg \°C$

$\Delta T_{water}$

Isolating $\Delta T$ from both equations:

$\Delta T_{soil}=\frac{Q_{soil}}{m_{soil}.C_{soil}}$ (3)

$\Delta T_{soil}=\frac{1 kcal}{1 kg(0.2 kcal/kg \°C)}$

$\Delta T_{soil}=5\°C$ (4)

$\Delta T_{water}=\frac{Q_{water}}{m_{water}.C_{water}}$ (5)

$\Delta T_{water}=\frac{1 kcal}{1 kg(1 kcal/kg \°C)}$

$\Delta T_{water}=1\°C$ (6)

Comparing (4) and (6) we can find the soil will be $4\°C$ warmer than the water.

8 0

4 years ago

Help me pretty please :)

Ostrovityanka [42]

Answer:

the 3 one is the answer the length of the wire in the magnetic

3 0

3 years ago

When two oppositely charged electrodes are immersed in a solution, positively charged ions are attracted to the negative electro

e-lub [12.9K]

Answer:

conductivity of solution is reduced.

Explanation:

When two oppositely charged electrodes are immersed in a solution, positively charged ions are attracted to the negative electrode and gain electrons. The negatively charged ions are attracted to the positive electrode and release electrons.

Due to the process mentioned above , the negatively charged ions are accumulated at the positive electrode and the positively charged ions are accumulated at the negative electrode . This accumulation prevents further attraction of ions at oppositely charged electrodes because the incoming ions face repulsion from already accumulated ions at electrodes. Further , it creates an emf acting in opposite direction . It reduces the current through the solution. Hence conductivity of solution is reduced.

5 0

3 years ago

Using steam tables, calculate the fugacity and fugacity coefficient of: (a) Superheated steam at 50.0 MPa and 500 ◦C. (b) Satura

VashaNatasha [74]

Answer:

Explanation:

G(T,P) - G(T,Po) = RT * ln(f/fo)

6 0

3 years ago