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Alex73 [517]
3 years ago
14

How would a planet move if the sun suddenly disappeared ?

Physics
1 answer:
777dan777 [17]3 years ago
6 0

Explanation:

The sun gravity keeps the solar system i.e planets in its place and orbits if there is no sun the planets would flying off and  It would be complete and utter chaos in our solar system

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If two black holes collide and they send out the gravitational waves and ripples, then what happens when 3 black holes collide?
tester [92]

Answer:

I don’t know

Explanation:

6 0
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Khaled said the North star is special because it appears all over the world and its changes position.
saw5 [17]
False the North Star never changes it position
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3 years ago
A mixture of nitrogen and water vapor at 200oF, 1 atm has the molar analysis of 80% N2, 20% water vapor.a) If the mixture is coo
Illusion [34]

Answer:

p_g = 57.64 lb/in^2

Explanation:

Given data:

temperature of water vapor is 200 degree F

pressure is 1 atm

\from the standard water temperature tables , at temperature  200 degree F

p_{sat}  = 11.538 psia

\omega_1 = \frac{0.622 \times 0.2 \times 11.538}{14.7 - (0.2\times 11.538)}

\omega_1 = 0.115

at temp 200 degree F and\omega _1 = 0.115

\phi = 0.255

so relative humidity is given as

\phi = \frac{p_v}{p_g}

0.255 = \frac{14.7}{p_g}

p_g = 57.64 lb/in^2

6 0
4 years ago
How can Newton's third law describe the forces affecting a rocket as it
rusak2 [61]

Answer:D

Explanation:

Apex

7 0
4 years ago
Boron coated with SiC (or Borsic) reinforced aluminum containing aligned 20 vol% fibers is an important high-temperature, lightw
Scilla [17]

Answer:

Option C is correct.

Modulus of elasticity of the composite perpendicular to the fibers = (12 × 10⁶) psi

Explanation:

For combination of materials, the properties (especially physical properties) of the resulting composite is a sum of the fractional contribution of each material thay makes up the composite.

In this composite,

The fibres = 20 vol%

Aluminium = 80 vol%

Modulus of elasticity of the composite

= [0.2 × E(fibres)] + [0.8 × E(Al)]

Modulus of elasticity of the fibers = E(fibres) = (55 × 10⁶) psi. =

Modulus of elasticity of aluminum = E(Al) = (10 × 10⁶) psi.

But modulus of elasticity of the composite perpendicular to the fibers is given in the expression.

[1 ÷ E(perpendicular)]

= [0.2 ÷ E(fibres)] + [0.8 ÷ E(Al)]

[1 ÷ E(perpendicular)]

= [0.2 ÷ (55 × 10⁶)] + [0.8 ÷ (10 × 10⁶)]

= (3.636 × 10⁻⁹) + (8.00 × 10⁻⁸)

= (8.3636 × 10⁻⁸)

E(perpendicular) = 1 ÷ (8.3636 × 10⁻⁸)

= 11,961,722.5 psi = (11.96 × 10⁶) psi

= (12 × 10⁶) psi

Hope this Helps!!!

6 0
3 years ago
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