Initial conditions:
m1 = 1.0 ; v1 = 5
m2 = 4.0 ; v2 = 0
In the case where the second object (sometimes called the target) is at rest the velocities after the condition are
v1' = v1* (m1-m2)/(m1+m2)
v2' = 2v1*m1/(m1+m2)
For this we get
v1' = 5*(-3)/5 = -3m/s (moving in the opposite direction as before at 3m/s
v2' = 2*5*(1)/5 = 2m/s in the same direction as the original ball was moving
you can see these directions by looking at the signs. The momenta also add to the initial momentum as required.
Answer:
Diameter of the piston would be 0.71 m (71.1 cm)
Explanation:
From the principle of pressure;
= 
Let 
= 2903.57 lb, 
= 24.41 lbs, 
= 3.26 cm = 0.0326 m.
= 
= 
x 
= 0.00334 
So that:
= 
= 
= 0.3973
= 0.4
The radius of the piston can be determined by:
=
0.3973 = x 
= 
= 0.1264
r = 
= 0.3555
r = 0.36 m
Diameter of the piston = 2 x r
= 2 x 0.3555
= 0.711
Diameter of the piston would be 0.71 m (71.1 cm).
Answer:
W = 200 J
Explanation:
Work will be equal to the change in kinetic energy
W = ½mv² - 0
W = ½(0.010)200²
W = 200 J
Answer:
B
Explanation:
If you pass white light through a blue filter, then only blue color will appear on the other end. This is because a blue filter will only allow blue light through it. And will absorb other color. In other words the rest colors would disappear. Hence the camera would receive just blue light. This phenomenon is referred to as color by subtraction.
The potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules
<h3>
What is the energy in a capacitor?</h3>
The energy stored in a capacitor is an electrostatic potential energy.
It is related to the charge(Q) and voltage (V) between the capacitor plates.
It is represented as 'U'.
<h3>
How to determine the potential difference</h3>
Formula:
Potential difference, V is the ratio of the charge to the capacitance of a capacitor.
It is calculated using:
V = Q ÷ C
Where Q = charge 5 × 10∧-5C and C = capacitance 10∧-9
Substitute the values into the equation
Potential difference, V = 5 × 10∧-5 ÷ 10∧-9 = 5 × 10∧4 volts
<h3>
How to determine the energy stored</h3>
Formula:
Energy, U = 1 ÷ 2 (QV)
Where Q= charge and V = potential difference across the capacitor
Energy, U = 1 ÷ 2 ( 5 × 10∧-5 × 5 × 10∧4)
= 0.5 × 25 × 10∧-1
= 0.5 × 2.5
= 1. 25 Joules
Therefore, the potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules
Learn more about capacitance here:
brainly.com/question/14883923
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