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timurjin [86]
3 years ago
13

Yosef is playing with different kinds of rubber bands. Some are very narrow and some are quite wide. Yosef is curious about the

rubber bands, and develops this scientific question: Does the width of a rubber band affect how easily it can be stretched?
He decides to develop a hypothesis to test this scientific question. What could Yosef's hypothesis be?
Physics
2 answers:
kari74 [83]3 years ago
4 0

Answer:

He could have many different hypothesis, but here is one.

Explanation:

If rubber bands are wider, then the rubber bands will stretch further, because the wider a rubber band is the stronger it is.

UkoKoshka [18]3 years ago
4 0
Please mark it as brainliest
Yosef hypothesis could be stretching of rubber band depends on rubber band's width. It is difficult to stretch a wider rubber band in comparison to a narrow band.
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What is the separation distance, in meters, between masses m1 = 15 x 107 kg and m2 = 62 x 107 kg when the gravitational force be
nalin [4]

Answer:

94.1 m

Explanation:

From Coulombs law,

F  = Gm1m2/r²................... Equation 1

where F = force, m1 = first mass, m2 = second mass, G = universal constant, r = distance of separation.

Make r the subject of the equation,

r = √(Gm1m2/F)................. Equation 2

Given: F = 7×10² N, m1 = 15×10⁷ kg, m2 = 62×10⁷ kg,

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute into equation 2

r = √( 6.67×10⁻¹¹×15×10⁷×62×10⁷/7×10²)

r √(886.16×10)

r √(88.616×10²)

r = 9.41×10

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3 0
3 years ago
The drawing shows an adiabatically isolated cylinder that is divided initially into two identical parts by an adiabatic partitio
Sveta_85 [38]

Answer:

temperature on left side is 1.48 times the temperature on right

Explanation:

GIVEN DATA:

\gamma = 5/3

T1 = 525 K

T2 = 275 K

We know that

P_1 = \frac{nRT_1}{v}

P_2 = \frac{nrT_2}{v}

n and v remain same at both side. so we have

\frac{P_1}{P_2} = \frac{T_1}{T_2} = \frac{525}{275} = \frac{21}{11}

P_1 = \frac{21}{11} P_2 ..............1

let final pressure is P and temp  T_1 {f} and T_2 {f}

P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}

P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3} ..................2

similarly

P_2^{-2/3} T_2^{5/3} = P^{-2/3} T_2 {f}^{5/3} .............3

divide 2 equation by 3rd equation

\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}

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6 0
3 years ago
A dog pushes against the front door for 3 seconds with a force of 88 N. What
kirill [66]

264Ns

Explanation:

Given parameters:

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Force of push = 88N

Unknown:

Impulse = ?

Solution:

Impulse is defined as the change in momentum of a body when force acts on it.

  Impulse = Force x time

Inputting the parameters:

    Impulse = 88 x 3 = 264Ns

Learn more:

Momentum brainly.com/question/9484203

#learnwithBrainly

5 0
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