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Colt1911 [192]
2 years ago
15

what is the answer to: At a​ little-known vacation​ spot, taxi fares are a bargain. A 64​-mile taxi ride takes 72 minutes and co

sts ​$57.60. You want to find the cost of a 31​-minute taxi ride. What unit price do you​ need?
Mathematics
1 answer:
Tcecarenko [31]2 years ago
4 0

Answer:

<h2>olol</h2>

Step-by-step explanation:

<h2>mobile legends kanalang lods</h2>
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Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
3 years ago
Friction causes vehicles, such as this truck, to use more what?
ziro4ka [17]

Answer:

A. Gasoline

Step-by-step explanation:

7 0
2 years ago
Para encher 2/5 de uma piscina são necessários 60.000 litros de água. Qual é a capacidade dessa piscina?
natali 33 [55]

Answer:

A capacidade dessa piscina é de 150.000 litros de água.

Step-by-step explanation:

A capacidade da piscina é de x.

Para encher 2/5 de uma piscina são necessários 60.000 litros de água.

Isto implica que:

\frac{2x}{5} = 60000

2x = 60000*5

x = \frac{60000*5}{2}

x = 150000

A capacidade dessa piscina é de 150.000 litros de água.

8 0
2 years ago
Brandon graphed one line in a system of equations. The system has only one solution, (0,3). Which equations could also be part o
AlladinOne [14]

Answer:

y = 3 and y = x + 3

Step-by-step explanation:

The equation y = 3 whose graph is a line parallel to x-axis can be a part of the system.

Consider the equation y = x + 3.

Substitute (0, 3).

3 = 0 + 3

So, (0, 3) lies on y = x + 3 and this can also be a part of the system.

6 0
2 years ago
Read 2 more answers
Can somebody help me plz with this math problem!!
Tema [17]

Answer:

Step-by-step explanation:

.

6 0
2 years ago
Read 2 more answers
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