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Pachacha [2.7K]
3 years ago
5

Water is separated into hydrogen and oxygen gas by electrolysis.

Chemistry
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

water is separated into hydrogen and oxygen gas by electrolysis is

Explanation:

both physical change and chemical change:

1) physical properties and form gets changed

2) Chemical change as the entire composition also gets changed

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find the volume of an item using a scale and waterA crown made of alloy of gold and silver has a volume of 60cm3and mass of 1050
KiRa [710]

Answer:

The mass of gold in crown is 960.61 g.And  the volume of gold is 49.77 cm^3.

Explanation:

Density is defined as mass of the substance present in unit volume of the substance.

Mass of gold in an alloy of crown= m

Mass of silver in an alloy of crown = M

Volume  gold in an alloy of crown= v

Volume of silver in an alloy of crown = V

Density of gold = 19.3 g/cm^3

Density of silver = 10.5 g/cm^3

Volume of the crown = 60 cm^3

60 cm^3=v+V

60 cm^3=\frac{m}{19.3 g/cm^3}+\frac{M}{10.5 g/cm^3}..(1)

Mass of eh crown = 1050 g

1050g =m+M..(2)

Solving equation (1) and (2):

m = 960.61 g

M = 89.39 g

Volume of the gold = v = \frac{960.61 g}{19.3 g/cm^3}=49.77 cm^3

Volume of silver = V = 60 cm^3-v=60 cm63-49.77 cm63=10.23 cm^3

The mass of gold in crown is 960.61 g.And  the volume of gold is 49.77 cm^3.

4 0
3 years ago
A system receives 575 ) of heat and delivers 425 ) of work. Calculate the change in the internal energy. AE, of the system.​
vfiekz [6]

Answer:

ΔE = 150 J

Explanation:

From first law of thermodynamics, we know that;

ΔE = q + w

Where;

ΔE is change in internal energy

q is total amount of heat energy going in or coming out

w is total amount of work expended or received

From the question, the system receives 575 J of heat. Thus, q = +575 J

Also, we are told that the system delivered 425 J of work. Thus, w = -425 J since work was expended.

Thus;

ΔE = 575 + (-425)

ΔE = 575 - 425

ΔE = 150 J

7 0
3 years ago
Identify the hybridization of each carbon atom for the molecule above
ipn [44]

Carbons starting from the left end:

  1. sp²
  2. sp²
  3. sp²
  4. sp
  5. sp

Refer to the sketch attached.

<h3>Explanation</h3>

The hybridization of a carbon atom depends on the number of electron domains that it has.

Each chemical bond counts as one single electron domain. This is the case for all chemical bonds: single, double, or triple. Each lone pair also counts as one electron domain. However, lone pairs are seldom seen on carbon atoms.

Each carbon atom has four valence electrons. It can form up to four chemical bonds. As a result, a carbon atom can have up to four electron domains. It has a minimum of two electron domains, with either two double bonds or one single bond and one triple bond.

  • A carbon atom with four electron domains is sp³ hybridized;
  • A carbon atom with three electron domains is sp² hybridized;
  • A carbon atom with two electron domains is sp hybridized.

Starting from the left end (H₂C=CH-) of the molecule:

  • The first carbon has three electron domains: two C-H single bonds and one C=C double bond; It is sp² hybridized.
  • The second carbon has three electron domains: one C-H single bond, one C-C single bond, and one C=C double bond; it is sp² hybridized.
  • The third carbon has three electron domains: two C-C single bonds and one C=O double bond; it is sp² hybridized.
  • The fourth carbon has two electron domains: one C-C single bond and one C≡C triple bond; it is sp hybridized.
  • The fifth carbon has two electron domains: one C-H single bond and one C≡C triple bond; it is sp hybridized.

8 0
3 years ago
Please explain how we judge the brightness of stars.
11111nata11111 [884]
Astronomers can measure it by way of luminosity which is the power of a star or the amount of energy (light) the star admits from its surface. they also measure the brightness of a start as if it were to appear 32.6 light years from Earth
6 0
3 years ago
What happened to the salt molecules when they were added to cold water
Nimfa-mama [501]
Cooler water molecules are denser than warm water and will not allow much of the salt to dissolve
8 0
3 years ago
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