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Bas_tet [7]
3 years ago
12

How many moles of sulfur are found in 2.86 * 10^21 atoms of sulfur?

Chemistry
1 answer:
wlad13 [49]3 years ago
3 0

Answer:

4.75x10^{-3}mol

Explanation:

Hello!

In this case, since the Avogadro's number is a large one that help us to figure out 1 mole of any substance contains 6.022x10²³ particles, say atoms, molecules or ions, in this case, for the given amount of atoms of sulfur, the corresponding moles are obtain down below:

2.86x10^{21}atoms*\frac{1mol}{6.022x10^{23}}\\\\4.75x10^{-3}mol

Best regards!

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3h2so4 2b(oh)3 - b2(so4)3 6h2o what is the mole ratio between water and sulfuric acid?
Nutka1998 [239]

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<h3>What is Sulfuric acid?</h3>
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8 0
1 year ago
A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate.2KClO3 Right arrow. 2KCI + 3O2What is the perce
STALIN [3.7K]

Answer:

73.4% is the percent yield

Explanation:

2KClO₃ →  2KCl  + 3O₂

This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.

We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃

In the theoretical yield of the reaction we say:

2 moles of potassium chlorate can produce 3 moles of oxygen

Therefore, 3.26 moles of salt, may produce (3.26 . 3) /2 = 4.89 moles of O₂

The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g

But, we have produced 115 g. Let's determine the percent yield of reaction

Percent yield = (Produced yield/Theoretical yield) . 100

(115g / 156.6g) . 100 = 73.4 %

5 0
3 years ago
N2 + 3H2, -&gt; 2NH3<br> If I have 50.6 L of N2 and excess H2, how many liters of NH3 can I produce?
Anastaziya [24]

Answer:

C. 101.2 L

Explanation:

N2 + H2= NH3

Balancing it,

N2 + 3 H2 = 2.NH3

(1 mol) (3 mol) (2 mol)

which means

1 molecule of nitrogen reacts with 3 molecule of hydrogen to form ammonia.

Likewise,

50.6 l of nitrogen reacts with 50.6 × 3= 151.8 l of hydrogrn to form 50.6 × 2= 101.2 l of ammonia.

3 0
3 years ago
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