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tankabanditka [31]
3 years ago
13

Answer please thanks for answer ​

Mathematics
1 answer:
zavuch27 [327]3 years ago
8 0

Answer: 15.8

In this number, .8 is the tenths place. So round it to this number.

.839 rounded to nearest tenth = .8

Your result should be 15.8.

15.839 rounded to the nearest tenth is 15.8.

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Find the distance between the two points in simplest radical form. (3,8) and (5, -1)​
ruslelena [56]

Answer: irk

Step-by-step explanation:

7 0
3 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
3 years ago
A submarine descends to 1/6 of its maximum depth. Then it descends another 2/3 of its maximum depth. If it is now at 650 feet be
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Answer:

7500 feet is the lowest sea level or half of the earth

Step-by-step explanation:

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8 0
2 years ago
How much does 6.1 cubic feet of water weigh in pounds
Dovator [93]

Answer:

380.832 pounds    Approximately

Step-by-step explanation:

1 foot of water = 62.428 pounds  (62.43)

6.1* 62.43= 380.832

6 0
3 years ago
The height of a tree in feet over x years is modeled by the function f(x). f(x)=301+29e−0.5x which statements are true about the
Karo-lina-s [1.5K]
Given this equation:

f(x)=301+29^{-0.5x}

That represents t<span>he height of a tree in feet over (x) years. Let's analyze each statement according to figure 1 that shows the graph of this equation.
</span>
The tree's maximum height is limited to 30 ft.

As shown in figure below, the tree is not limited, so this statement is false.

<span>The tree is initially 2 ft tall

The tree was planted in x = 0, so evaluating the function for this value, we have:

</span>f(0)=301+29^{-0.5(0)}=301+1=302ft
<span>
<span>So, the tree is initially \boxed{302ft} tall.
</span>
Therefore this statement is false.

</span>Between the 5th and 7th years, the tree grows approximately 7 ft.
<span>
if x = 5 then:

</span>f(5)=301+29^{-0.5(5)}=301ft<span>

</span>if x = 7 then:

f(7)=301+29e^{0.5(7)}=301ft

So, between the 5th and 7th years the height of the tree remains constant
:
\Delta=f(7)-f(5)=301-301=0ft

This is also a false statement.

<span>After growing 15 ft, the tree's rate of growth decreases.</span>

It is reasonable to think that the height of this tree finally will be 301ft. Why? well, if x grows without bound, then the term 29^{-\infty} approaches zero.

Therefore this statement is also false.

Conclusion: After being planted this tree won't grow. 


4 0
3 years ago
Read 2 more answers
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