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tankabanditka [31]
3 years ago
13

Answer please thanks for answer ​

Mathematics
1 answer:
zavuch27 [327]3 years ago
8 0

Answer: 15.8

In this number, .8 is the tenths place. So round it to this number.

.839 rounded to nearest tenth = .8

Your result should be 15.8.

15.839 rounded to the nearest tenth is 15.8.

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What color is a carrot
777dan777 [17]

Answer:

uh i think its a carrot uh

Step-by-step explanation:

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5 0
2 years ago
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What is the value of x so that the line segment with endpoints W(x, −2) and X(5, −4) is parallel to the line segment with endpoi
coldgirl [10]

Answer:

x equals six start fraction one over two end fraction

Step-by-step explanation:

Segments which are parallel have the same slope. Find the slope of of YZ. Then using that value, find the slope WX and solve for the value of x.

Slope of YZ is:

m = \frac{y_2-y_1}{x_2-x_1}=\frac{2-6}{2-5}=\frac{-4}{-3}=\frac{4}{3}

Since they are parallel, then WX has a slope of 4/3 too.

Slope of WX is:

m = \frac{y_2-y_1}{x_2-x_1}\\\\\frac{4}{3}=\frac{-2--4}{x-5}\\\\\frac{4}{3}=\frac{2}{x-5}\\\\\frac{4}{3} (x-5) = 2\\\\4x -20=6\\\\4x = 26\\\\x = 6\frac{1}{2}

5 0
2 years ago
Match the following rational expressions to their rewritten forms.
Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}

And the rewritten forms:

(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}

So, correct option is 3.

(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}

So, correct option is 1.

(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}

So, correct option is 2.

(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}

So, correct option is 4.

The answer is also attached in the answer area.

7 0
2 years ago
I am so stupid but I hope someone can help with this one.
Snezhnost [94]
I'm sure your not that stupid just post a qeustion and I will help you.
6 0
3 years ago
25 POINTS!!!!!
Alborosie
180-92=88 the answer is 88 because a line is equal to 180 degrees and you got one angle equaling 92 degrees so you just subtract 180 minus 92, getting you angle 8 to be 88 degrees
3 0
3 years ago
Read 2 more answers
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