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TiliK225 [7]
2 years ago
9

We have noted that there can be no input queuing if the switching fabric is n times faster than the input line rates, assuming n

input lines all have the same rate. Explain why this is the case.
Computers and Technology
1 answer:
Ostrovityanka [42]2 years ago
7 0

Consider the given data:

Assume packet length=n

Maximum queuing delay= (n–1)D

All packets are of the same length, n packets arrive at the same time to the n input ports, and all n packets want to be forwarded to different output ports.

a)  The maximum delay for a packet for the memory = (n-1)D

b)  The maximum delay for a packet for the bus = (n-1)D

c)  The maximum delay for a packet for the crossbar switching fabrics=  0

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Write the following function without using the C++ string class or any functions in the standard library, including strlen(). Yo
dolphi86 [110]

Answer:

The function in C++ is as follows

int chkInd(string str1, string str2){    

int lenstr1=0;

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int index = 0; int retIndex=0;

for(int i=lenstr1-1;i>=0; i--){

   while (str2[index] != '\0'){

       if (str1[i] == str2[index]){

           retIndex=1;

           break;         }

       else{   retIndex=0;      }

  index++;    }

  if (retIndex == 0){   return i;   }else{return -1;}}

}

Explanation:

This defines the function

int chkInd(string str1, string str2){    

First, the length of str1 is initialized to 0

int lenstr1=0;

The following loop then calculates the length of str1

while(str1[lenstr1] != '\0'){  lenstr1++;  }

This initializes the current index and the returned index to 0

int index = 0; int retIndex=0;

This iterates through str1

for(int i=lenstr1-1;i>=0; i--){

This loop is repeated while there are characters in str2

   while (str2[index] != '\0'){

If current element of str2 and str1 are the same

       if (str1[i] == str2[index]){

Set the returned index to 1

           retIndex=1;

Then exit the loop

           break;         }

If otherwise, set the returned index to 0

       else{   retIndex=0;      }

Increase index by 1

  index++;    }

This returns the calculated returned index; if no matching is found, it returns -1

  if (retIndex == 0){   return i;   }else{return -1;}}

}

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Answer:

The first one

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