All categories

2 years ago

4Na + O2 2Na2O

1 answer:

5 0

4
N
a
+
O
2
→
2
N
a
2
O
.
By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol
N
a
2
O
should result.
Explanation:
The molecular mass of natrium oxide is
61.98

g
⋅
m
o
l
−
1
. If
5

m
o
l
natrium react, then
5
2

m
o
l
×
61.98

g
⋅
m
o
l
−
1

=

154.95

g
natrium oxide should result.
So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go

You might be interested in

In cucumbers, green skin (G) is dominant to striped skin (g). If a farmer crosses a heterozygous (hybrid) cucumber with a homozy

Elena L [17]

Answer:

Half will be green and half will be striped

Explanation:

Given green skin (G) is dominant to striped skin (g).

Cucumber 1 : Heterozygous (Gg)

Cucumber 2 : Homozygous striped (gg)

When Gg X gg :

G g

g Gg gg

Half of the offspring will have Gg genotype so they will be green. Other half will have gg genotype so they will be striped.

8 0

2 years ago

I need help with this

lubasha [3.4K]

The answer is untestable

5 0

2 years ago

How many moles of chlorine (Cl) atoms are in a sample of 1.72 × 1022 atoms? 0.0286 mol Cl 35.0 mol Cl 1.03 × 1023 mol Cl 1.04 ×

kogti [31]

Given information : Sample of $1.72\times 10^{22} atoms$

We need to find the moles of Chlorine in the given sample.

We can say that we need to find moles from the given atoms.

Relation between mole and atom is given by : $1 mole = 6.022\times 10^{23} atoms$

Where $6.022\times 10^{23}$ is Avogadro number.

$1.72\times 10^{22} atoms\times \frac{1 mole}{6.022\times 10^{23} atoms}$

$1.72\times 10^{22}\times \frac{1 mole}{6.022\times 10^{23}}$

On solving the above equation , atoms(unit) gets cancelled out and we get 0.0286 mol.

In the given sample the moles of Chlorine (Cl) is 0.0286 mol , so option A is correct.

6 0

2 years ago

What is the ionic compound of Na^+ and CO3^2-

maksim [4K]

To find the chemical formula of an ionic compound, the first step is to find the charge of the 2 ions. As given already, the charge of sodium ion is 1+, and carbonate ion has a charge of 2-. We can picture it like that: Sodium ion loses 1 electron and carbonate ion gains 2.

The next step is to find how the 2 ions can lose and gain electrons equally. In this case, since each Na ion only loses 1 electron, it cannot satisfy the need of one carbonate ion, since they need 2, not 1. Therefore, 2 Na ions can cover the need of one carbonate ion. So, the ratio of Na to CO3 ion should be 2:1.

Now just combine the 2 ions, positive one at the front, which makes it NaCO3, make sure you do not add the charge and notice that CO3 is a molecule itself so do not remove the 3. Now because the ratio is 2:1, so the final formula is Na2CO3, no need to add 1 if the ratio is 1.

Your answer should be Na2CO3.

8 0

2 years ago

The half-life of krypton-91 (91Kr) is 10 s. At time t = 0 a heavy canister contains 7 g of this radioactive gas. (a) Find a func

Vlad1618 [11]

Answer:

misteri Cell ini quest ia half-life of beauty of misteri best, of Cell can't answer =

Explanation:

$\sqrt[ \geqslant { { | \geqslant | \geqslant \sqrt[ \gamma \% log_{ \tan( \sqrt[ < \pi \sqrt[ | \geqslant \sqrt[ < \leqslant |x| ]{y} | \times \frac{?}{?} ]{?} ]{?} ) }(?) ]{?} | | }^{2} }^{?} ]{ \sqrt[ < \gamma log_{ \frac{ | \geqslant y \sqrt[ |x \sqrt{ |?| } | ]{?} | }{?} }(?) ]{?} }$

5 0

2 years ago