4 N a + O 2 → 2 N a 2 O . By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol N a 2 O should result. Explanation: The molecular mass of natrium oxide is 61.98
g ⋅ m o l − 1 . If 5
m o l natrium react, then 5 2
m o l × 61.98
g ⋅ m o l − 1
=
154.95
g natrium oxide should result. So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go
