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Nadya [2.5K]
3 years ago
12

Which band is the smallest within the electromagnetic spectrum? A) X rays B) microwaves C) radio waves Eliminate D) visible ligh

t
Chemistry
2 answers:
babymother [125]3 years ago
6 0

Answer:

Visible light is the smallest band listed.

Explanation:

There are many different frequencies of radio, microwave and X Rays, but only a small band of light that we can observe.

aev [14]3 years ago
4 0
Radio   wave  eliminate  band (answer  c) is  smallest   within  electromagnetic  spectrum.
  
   The  electromagnetic  spectrum  is  the  range  of  frequencies  (the  spectrum)  of    electromagnetic  radiation   and  their  respective  wavelength and  photon  energies.  The   electromagnetic  spectrum  range from   radio  waves  to  gamma  rays.Radio waves  has  the  shortest  wavelength  while   gamma rays  has  highest.
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A series circuit has two 5.0-ohm resistors and a power source of 9.0 volts. How will the current be affected and what will it be
miskamm [114]
The formula for solving current given with resistance and power source or voltage is shown below:
I = V/R  

When two 5 ohms resistors are in series, we have:
I = 9 volts / (5+5 ohms)
I = 0.9 amperes

When it is being added with another 7.5 resistors, we have:
I = 9 volts / (5+5+7.5 ohms)
I = 0.529 ampere

The answer to the question is the letter "D. decrease; 0.51 amps".
3 0
3 years ago
For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. KNO3 →
Vinvika [58]

Answer : The oxidizing element is N and reducing element is O. 

KNO_{3} is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

KNO_{3} \rightarrow KNO_{2} +O_{2}

KNO_{3}  act as an oxidizing agent.

The oxidation number of N in KNO_{3} is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in KNO_{2}  is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number  reduced this means KNO_{3} itself get reduced to KNO_{2} and it can act as an oxidizing agent.

KNO_{3}  act as a reducing agent.

KNO_{3} \rightarrow KNO_{2} +O_{2}

The oxidation number of O in KNO_{3} is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in O_{2} is Zero (o).

Now, we conclude that the oxidation number increases this means KNO_{3} itself get oxidized to O_{2} and it can act as reducing agent.





                     

4 0
4 years ago
Read 2 more answers
Which of the following black body curves is representative of stars like our sun?
Bumek [7]
The answer is B
I also did this quiz.
7 0
3 years ago
To balance a chemical equation it may be necessary to adjust the
Mars2501 [29]

Answer:

  • <em>To balance a chemical equation it may be necessary to adjust the </em><u>coefficients.</u>

Explanation:

The <em>coefficients</em> of a <em>chemical equation</em> are the numbers that you put in front of each reactant and product. They are used to balance the equation and comply with the law of mass conservation.

By adjusting the coefficients you obtain the relative amounts (moles) of each product and reactant, i.e. the mole ratios.

Here an example.

The first information is what is called a word equation. E.g. nitrogen and hydrogen react to form ammonia:

  • Word equation: hydrogen + nitrogen → ammonia

  • Skeleton equation: H₂ + N₂ → NH₃

        This equation shows the chemical formulae but it is not balanced. The law of mass conservation is not observed.

So, in order to comply with the law of mass conservation you adjust the coefficients as follow.

  • Balanced chemical equation: 3H₂ + N₂ → 2NH₃

        As you see, it was necessary to modify the coefficients. Now the law of conservation of mass is observed and you get the mole ratios:

  • 3 mol H₂ : 1 mol  N₂ : 2 mol NH₃

       

4 0
3 years ago
Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reactio
umka21 [38]

Answer : The value of K_p at this temperature is 66.7

Explanation : Given,

Pressure of PCl_3 at equilibrium = 0.348 atm

Pressure of Cl_2 at equilibrium = 0.441 atm

Pressure of PCl_5 at equilibrium = 10.24 atm

The balanced equilibrium reaction is,

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{PCl_5})}{(p_{PCl_3})(p_{Cl_2})}

Now put all the values in this expression, we get :

K_p=\frac{(10.24)}{(0.348)(0.441)}

K_p=66.7

Therefore, the value of K_p at this temperature is 66.7

4 0
3 years ago
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