i think its 2/3 but im not sure .
Answer:15
Step-by-step explanation: Debora has to take the numbers 3 and 5 and multiply. 3x5= 15
Answer:
Step-by-step explanation:
(ﾉ◕ヮ◕)ﾉ*:･ﾟ✧
![\dfrac{8}{5} - \left[-\dfrac{2}{3}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B8%7D%7B5%7D%20-%20%5Cleft%5B-%5Cdfrac%7B2%7D%7B3%7D%5Cright%5D)
<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
ANSWER
Possible rational roots: <span><span>±1,±2,±3,±4,±6,±12</span><span>±1,±2,±3,±4,±6,±12</span></span>
Actual rational roots: <span><span>1,−1,2,−2,−3</span></span>
<span><span>see attachments for all steps.</span></span>
