All categories

2 years ago

What is the meaning of Post war?

Mathematics

1 answer:

Licemer1 [7]2 years ago

3 0

Post war means the time after a war had just taken place

You might be interested in

Answer both question for 20 points and brainliest

Dmitrij [34]

Answer:

1 - c

2 - A

Step-by-step explanation:

Hey There!

So for the first one we are given the dimensions of a rectangular prism and they want us to find the volume

Remember to find the volume we use the equation

V = length x width x height

so we just plug in the values

v = 2.6 x 2.1 x 3.9 = 21.294

the closest is 20 so C is your answer

For the second one we are given a triangular prism

and they want us to find the volume

$V=\frac{1}{2} bhl$

b = base (10.3)

l = length (4)

h = height (7)

7x4=28

28x10.3=288.4

then we divide by 2

288.4/2=144.2

so your selected answer is correct

4 0

2 years ago

Order these numbers in order 0.5, 1 1/4, 0.25, 3/8

vodomira [7]

Answer:

0.5,0.25,3/8,1 1/4

Step-by-step explanation:

3 0

2 years ago

Please help a girl out I'm so confused

Sloan [31]

Answer:

A= 16 B=28

Step-by-step explanation:

So the ration is 4:7, you have to find multiples that have that same ratio

Multiply both numbers by 4, this should get you

16:28

16 + 28 = 44

Therefore this is the correct answer

5 0

2 years ago

What is -16-15????????????

frozen [14]

Answer:

Step-by-step explanation:

to lazy

6 0

2 years ago

Read 2 more answers

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

5 0

2 years ago