That is the final answer to this question
42765
You HAVE to use Pemdas.
2[3(4^2+1)]-2^3
2(3(16+1))-2^3
2(3(17))-2^3
2*51-2^3
102-8
94.
Explanation: you use Pemdas P-parenthesis
E-exponents
M-multiplication
D-division
A-addition
S-subtraction
The y-coordinate is between -1 and -2. It is close to halfway between -1 and -2, but it is a little less than halfway.
Answer: Choice B. 
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
x = 6.6
Step-by-step explanation:
Data obtained from the question include the following:
Angle X = 15°
Angle Y° = 23°
Side y = 10
Side x =..?
The value of side x can be obtained by using the sine rule as shown below:
x/Sine X = y/Sine Y
x/Sine 15 = 10/Sine 23
Cross multiply
x × Sine 23 = 10 × Sine 15
Divide both side by Sine 23
x = (10 × Sine 15) / Sine 23
x = 6.6
Therefore, the value of x is 6.6.
