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2 years ago

Help me answer pls thanks.Dont answer if ur just put nothing or you dont know.

Mathematics

1 answer:

raketka [301]2 years ago

8 0

Hi I want the points thanks

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In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older

earnstyle [38]

Answer:

Step-by-step explanation:

In the past, mean of age of employees

i.e. $\mu = 40$

Recently sample was taken

n = sample size = 60

Mean of sample = 45

Std dev of sample s = 16

$H_0: \bar x = 40\\H_a: \bar x >40$

(Right tailed test)

Since only population std deviation is known we can use t test only

Std error = $\frac{s}{\sqrt{n} } \\=\frac{16}{\sqrt{61} } \\=2.049$

Mean difference = 45-40 =5

Test statistic t= $\frac{5}{2.049} \\=2.441$

df = 60

p value =0.008739

Since p < 0.05 we reject null hypothesis

The mean age has increased.

5 0

2 years ago

Water drips from a faucet at a rate of 41 drops/minute. Assuming there are 15,000 drops in a gallon, how many minutes would it t

ELEN [110]

Answer:

366 minutes

Step-by-step explanation:

divide 15000 by 41

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3 years ago

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Classify the polynomial 2x3 + 6x2 - 4 by the number of terms.

Andrej [43]

Answer:

trinomial

Step-by-step explanation:

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2 years ago

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Who of the following functions is graphed

erastovalidia [21]

The following function would be a or d

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2 years ago

100 POINTS AND BRAINLIEST

zysi [14]

Answer:

8 square units and $\frac{40}{3}$ square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor $\frac{1}{3},$ then

$\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.$

2. Triangles ABC and DBE are similar with scale factor $\frac{2}{3},$ then

$\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.$

3. Thus, the area of the quadrilateral DFGE is

$A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.$

and the area of the quadrilateral ADEC is

$A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.$

4 0

2 years ago

Read 2 more answers

Help me answer pls thanks.Dont answer if ur just put nothing or you dont know. ​

Help me answer pls thanks.Dont answer if ur just put nothing or you dont know.