The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.
Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that
L = 2W - 5
Substituting L into P, we have
P = 2(2W - 5 + W)
P = 2(W - 5)
Since P = 56, we have
2(W - 5) = 56
~Dividing both sides by 2, we have
W - 5 = 56/2
W - 5 = 23
Adding 5 to both sides, we have
W = 23 + 5
W = 28 inches
Substituting W into L, we have
L = 2W - 5
L = 2(28) - 5
L = 56 - 5
L = 51 inches
So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Learn more about perimeter of a rectangle here:
brainly.com/question/16715918
Answer:
I'd say about 45 degrees :)
Step-by-step explanation:
B.
if it's is a right angle triangle, two of the x-coordinate of the points must be the same however with the points given, we can tell that the x coordinates are different , the two points are not vertical hence it does not form a right angle triangle.
8-9n=15 I believe
At least I hope
Pythagoras theorem I guess
