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Stells [14]
3 years ago
6

Find the sum of the first 10 terms of the following geometric sequences: {3, 6, 12, 24, 48...)

Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

Answer:

3069

Step-by-step explanation:

q=6/3=2

s10=3(2^10-1)÷(2-1)=3×(1024-1)=

3069

because sn=a1(q^n-1)/(q-1)

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