Answer:
the answer is 546 hope this helps :)
Step-by-step explanation:
First we find the common difference...to do this we subtract the first term from the second term. -7 - (-1) = -7 + 1 = -6
now we are going to find the 10th term
an = a1 + (n-1)*d <== formula for finding any term in arithmetic series
a1 = 1st term, d = common difference, n = term we want to find
now we sub
a10 = -1 + (10 -1) * -6
a10 = -1 + (9 * -6)
a10 = -1 - 54
a10 = - 55
now we will find the sum
Sn = (n (a1+ an)) / 2 <== formula for finding the sum
S10 = (10(-1 - 55))/2
S10 = (10(-56) / 2
S10 = -560/2
S10 = - 280
so the sum of the first 10 numbers is -280
Answer:
Explanation:
First you need to factor out the GCF (greatest common factor) of the numbers, which is 8n.
The GCF cancels out on top and bottom so it becomes:
Answer:
30 boxes of tea
Step-by-step explanation:
27 (overall tea boxes) - 12 (boxes sold) = 15
15 (leftover boxes) x 18 (kg of each box) = 270
270 (overall kg of the boxes) divided by 9 (kg of the bags) = 30, so all the tea boxes can be placed into the bags
Answer:
Step-by-step explanation:
radius=16/2=8 units
d=12 cm
reqd. length=√(12²-8²)=√(144-64)=√80=4√5 units
