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monitta
3 years ago
9

My little sister need help with this problem. Annabelle arranged her 42 building blocks into 3 rows of 14 blocks. Then, she rear

ranged them into 6 rows of 7 blocks. What two other factor pairs could Annabelle use to help her rearrange the blocks again?
Explain your answer using complete sentences.
Mathematics
2 answers:
Tcecarenko [31]3 years ago
7 0
Annabelle could arrange her blocks in one row of 42 building blocks as 1 times 42 = 42.

She could also arrange her blocks in 2 rows of 21 blocks because 2 times 21 is also 42.
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

21 rows and two Blocks

1 row 42 Blocks

Step-by-step explanation:

Number of blocks with Annabelle = 42

First arrangement = 3 rows 14 blocks

Second arrangement = 6 rows 7 blocks

Solution

The other two factor pairs that could be used to rearrange the blocks again?

Solution:

Here, we will have to find the factor pairs of total number of blocks present with Annabelle.

i.e. 42

First of all, let us have a look at the factor pairs of 42.

Therefore, the other two factor pairs can be 2, 21 and 1, 42.

The other two possible factor pairs are:

21 rows 2 blocks

1 row 42 blocks

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_______________________________________

4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

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Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

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