How does this pendulum demonstrate the law of conservation of energy?

The product of an object's mass and velocity is it's

Leviafan [203]

Answer:

C) Momentum

Explanation:

Refers to an objects mass in motion.

5 0

2 years ago

A convex, or converging, lens with a focal length of 34 cm is used to observe an image of an apple than is 80 cm away from the l

Hatshy [7]

The image distance is 59.2 cm and the image is real and small.

<h3>Image distance</h3>

The distance of the image formed by the convex or converging lens is determined by applying the following lens equation.

1/f = 1/u + 1/v

where;

f is the focal length = 34 cm
u is the object distance = 80 cm
v is the image distance = ?

1/v = 1/f - 1/u

1/v = 1/34 - 1/80

1/v = 0.0294 - 0.0125

1/v = 0.0169

v = 1/0.0169

v = 59.2 cm

Thus, the image distance is 59.2 cm and the image is real and small.

Learn more about convex lens here: brainly.com/question/10153605

8 0

2 years ago

An object starts from rest at the origin (x0 = 0) and travels in a straight line with a constant acceleration (a = constant). Su

agasfer [191]

Answer:

$a=(6.8)\ m/s^2$

Explanation:

Given that,

An object starts from rest at the origin (x₀ = 0) and travels in a straight line with a constant acceleration (a = constant).

The relation between the position (x) and time (t) is given by :

$x=(3.4t^2)\ m/s^2$

Let v is the velocity of the object.

$v=\dfrac{dx}{dt}$

$v=\dfrac{d(3.4t^2)}{dt}$

$v=(6.8t)\ m/s$

Let a is the acceleration of the object. It is given by :

$a=\dfrac{dv}{dt}$

$a=\dfrac{d(6.8t)}{dt}$

$a=(6.8)\ m/s^2$

So, the acceleration of the object is $(6.8)\ m/s^2$ . Hence, this is the required solution.

4 0

3 years ago

Explain what the purpose of projectile motion is, and the different equations used. Explain what each equation does.

Len [333]

Answer:

MY friend has already described the purpose of projectile motion so I will quickly go through the uses of each equation ...

Explanation:

TIME OF FLIGHT = it is given as 2Usin tita/g...it is the total time taken to and fro...it is 2x of the time taken ....

TIME taken ..t= Usin tita / g.....is the time taken to reach the maximum height which is 1/2 the TOTALTIME OF FLIGHT GIVEN ABOVE ..

MAXIMUM HEIGHT: the maximum height is the height attained by the projectile when projected ...it is calculate using the formula = U^2 sin^2 tita / 2g

Range =Search Results

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An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin ⁡ 2 θ i g .

3 0

3 years ago

If a 230 gram object falls from 2 meters, what is its impulse and velocity upon impact?

anastassius [24]

1.44Ns

6.3m/s

Explanation:

Given parameters:

Mass of object = 230g = 0.23g

height of fall = 2m

Unknown:

Impulse = ?

velocity on impact = ?

Solution:

We are going to apply one of the equations of motions to solve this problem.

The most appropriate one is:

V² = U² + 2gH

where V is the final velocity

U is the initial velocity

g is acceleration due to gravity as the body falls with aid of gravity = 9.8m/s²

H is the height of fall

since the body was initially at rest, U = O

V² = 2gH

V = √2 x 9.8 x 2 = 6.3m/s

Impulse = mass x velocity = 0.23 x 6.3 = 1.44Ns

learn more:

momentum brainly.com/question/2990238

velocity brainly.com/question/10932946

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5 0

4 years ago