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Paladinen [302]

3 years ago

11

Which factors could be potential sources of error in the experiment? check all that apply.

2 answers:

Vadim26 [7]3 years ago

6 0

(A)energy lost in the lever due to friction

(C) visual estimation of height of the beanbag

(E)position of the fulcrum for the lever affecting transfer of energy

WARRIOR [948]3 years ago

6 0

Answer:

The Correct Answer is A, C, and E.

Explanation:

There are many potential sources of errors when designing and carrying pout experiments.

Personal error: Inaccurate observation by observers, If the data collecting has two observers and they have collected two different data which is not matching with the experiment data then it would be considered as the Observer or personal error.
Instrumental errors: If Calibration of the instruments is not carried out correctly then it will produce incorrect data then it will be categorized under Instrumental error of experiment.

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3 years ago

Which best compares and contrasts Banking and Investment Planning?

valina [46]

Answer:

Its C i think

Explanation:

makes the most sense

4 0

3 years ago

How many visible stars does How many visible stars Taurus “the bull” have

dolphi86 [110]

Answer:

The Taurus "bull" is home to 500 stars, six of which are visible to the naked eye.

Explanation:

4 0

3 years ago

Two blocks of masses 20 kg and 8.0 kg are connected togetherby

OleMash [197]

Answer:

14 N

Explanation:

The tension in the second string is puling both the masses of 20 kg and 8 kg with acceleration of 0.5 m s⁻²

So tension in the second string = total mass x acceleration

= 28 x .5 = 14 N . Ans..

4 0

3 years ago

The index of refraction for a certain type of glass is 1.641 for blue light and 1.603 for red light. When a beam of white light

exis [7]

Answer:

The angle between the emergent blue and red light is $0.566^{o}$

Explanation:

We have according to Snell's law

$n_{1}sin(\theta _{i})=n_{2}sin(\theta _{r})$

Since medium from which light enter's is air thus $n_{1}=1$

Thus for blue incident light we have

$1\times sin(40.05)=1.641\times sin(\theta _{rb})\\\\\therefore \theta _{rb}=sin^{-1}(\frac{sin(40.05)}{1.64})\\\\\theta _{rb}=23.10$

Similarly using the same procedure for red light we have

$1\times sin(40.05)=1.603\times sin(\theta _{rr})\\\\\therefore \theta _{rr}=sin^{-1}(\frac{sin(40.05)}{1.603})\\\\\theta _{rr}=23.66^{o}$

Thus the absolute value of angle between the refracted blue and red light is

$|23.66-23.10|=0.566^{o}$

6 0

3 years ago