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3 years ago

15 points Plz help me no links

Physics

2 answers:

wolverine [178]3 years ago

7 0

Answer:

alternating mountain ranges and valley.

Hope u find this helpful

ANEK [815]3 years ago

7 0

Answer:

I think you would like change where the mountains/basins are...

Explanation:

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If the pressure of gas is doubled and its absolute temperature is quadrupled, the volume is what factor times the original?

Lapatulllka [165]

Answer:

Volume will increase by factor 2

So option (A) will be correct answer

Explanation:

Let initially the volume is V pressure is P and temperature is T

According to ideal gas equation $PV=nRT$ , here n is number of moles and R is gas constant

So $V=\frac{nRT}{P}$ ....................eqn 1

Now pressure is doubled and temperature is quadrupled

So new volume $V_{new}=\frac{nR4T}{2P}=\frac{2nRT}{P}$ ........eqn 2

Now comparing eqn 1 nad eqn 2

$V_{new}=2V$

So volume will increase by factor 2

So option (A) will be correct answer

8 0

3 years ago

A car engine burns fuel and has moving parts. Sometimes, an engine can become too hot and overheat. What can prevent the engine

arsen [322]

there many things you could do, one is try getting a cooling system, another thing is its extramly hot and you may need to tunr off your car to prevent the engine from over heating.

6 0

4 years ago

Read 2 more answers

Which best compares radiation and conduction?

Karolina [17]

Answer:

The statements that best compares radiation and conduction are the following: both transfer thermal energy from warm objects to cooler objects and both can transfer energy through matter. The difference is that conduction is through direct heat transfer; whereas, radiation transfers heat through waves.

6 0

3 years ago

Read 2 more answers

An object weighs 79.1 N in air. When it is suspended from a force scale and completely immersed in water the scale reads 21.8 N.

Free_Kalibri [48]

Answer:

(a). The density of the object is 1382 kg/m³.

(b). The density of the oil is 536.4 kg/m³.

Explanation:

Given that,

Weight in air = 79.1 N

Weight in water = 21.8 N

Weight in oil = 48.4 N

We need to calculate the volume of object

Using formula of buoyant force

$F_{b}=W_{air}=W_{water}$

$F_{b}=79.1-21.8$

$F_{b}=57.3\ N$

$F_{b}=\rho g h$

Put the value into the formula

$57.3=1000\times V\times 9.8$

$V=\dfrac{57.3}{1000\times9.8}$

$V=5.84\times10^{-3}\ m^3$

We need to calculate the density

Using formula of buoyant force

$F_{b}=\rho Vg$

$79.1=\rho\times5.84\times10^{-3}\times9.8$

$\rho=\dfrac{79.1}{5.84\times10^{-3}\times9.8}$

$\rho=1382\ kg/m^3$

The density of the object is 1382 kg/m³.

(b). We need to calculate the volume of object

Using formula of buoyant force

$F_{b}=W_{air}=W_{oil}$

$F_{b}=79.1-48.4$

$F_{b}=30.7\ N$

We need to calculate the density

Using formula of buoyant force

$F_{b}=\rho_{oil} Vg$

$30.7=\rho_{oil}\times5.84\times10^{-3}\times9.8$

$\rho_{oil}=\dfrac{30.7}{5.84\times10^{-3}\times9.8}$

$\rho=536.4\ kg/m^3$

The density of the oil is 536.4 kg/m³.

Hence, This is the required solution.

4 0

3 years ago

When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is

padilas [110]

Answer:

$P_{C} = 3.2\, atm$

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

$P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T$