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Contact [7]
3 years ago
10

1/4 ,1/2, 1, 2, solve for a10

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
3 0

Answer: {a}_{10} = 128

Step-by-step explanation:

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Solve the differential equation by variation of parameters, subject to the initial conditions y(0) = 1, y'(0) = 0. 36y'' − y = x
viktelen [127]
Try this solution, note, checking was not performed.

5 0
3 years ago
Use the simple interest formula to find the ending balance 5000 at 5% for 3.5 years
Evgesh-ka [11]

Answer:

Given:  Principal(P) = $ 5000 , T = 3.5 years and R = 5%.

Using the formula of Simple Interest (I) given by;

I = \frac{P\times R \times T}{100} .......[1] , where P is the Principal amount of money to be invested, R be the rate of interest and T be the time.

Substitute the given values of P ,  R and T in [1] we have;

I = \frac{P \times R \times T}{100} = \frac{5000\times 5 \times 3.5}{100}

I = 50 \times 5 \times 3.5 = 250 \times 3.5

Simplify:

I = \$ 175

An Ending balance is calculated by subtracting cash outflows, interest paid for financing and principal paid on financing.

Ending Balance = $ 5000 + $ 175 = $ 5,175.

Therefore, the ending balance is $ 5,175



3 0
3 years ago
Natalie is flying a kite, holding her hands a distance of 2.5 feet above the ground and
Grace [21]

Answer:

50

Step-by-step explanation:

trust me bro

7 0
3 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
Leni [432]

Answer:  \dfrac{2x^2-1}{x(x^2-1)}

Step-by-step explanation:

The given function : y=\ln(x(x^2 - 1)^{\frac{1}{2}})

\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}    [\because \ln(ab)=\ln a +\ln b]

\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}  [\because \ln(a)^n=n\ln a]

Now , Differentiate both sides  with respect to x , we will get

\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1) (By Chain rule)

[Note : \dfrac{d}{dx}(\ln x)=\dfrac{1}{x}]

\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)

[ \because \dfrac{d}{dx}(x^n)=nx^{n-1}]

=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}

Hence, the derivative of the given function is \dfrac{2x^2-1}{x(x^2-1)} .

8 0
3 years ago
Place the steps for finding f'(X) in the correct order.<br><br><br> Plz help <br> Thank you!
SashulF [63]

Answer:

See below

Step-by-step explanation:

Given function is ,

=> f(x) = 4x + 7.

Replace f(x) with y ,

=> y = 4x + 7

For finding the inverse , interchange x and y ,

=> x = 4y + 7

Now solve for y ,

=> 4y = x - 7

=> y = x-7/4

Replace y with f-¹(x) ,

=> f-¹(x) = (x-7)/4

These are the required steps .

8 0
2 years ago
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