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3 years ago

I don’t understand this at all, if someone could help me please

Chemistry

1 answer:

rewona [7]3 years ago

6 0

Ok,

So what don't you understand. The whole page

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Question 3 0 / 1 point How many grams of carbon atoms are present in a sample of C3H8 if there are 4.10 moles of hydrogen atoms

hodyreva [135]

Answer:

18.45 g of C

Explanation:

This is a problem of rules of three:

1 mol of C₃H₈ contains 3 moles of C and 8 moles of H

If 8 moles of H are contained in 1 mol of propane

4.10 moles of H are contained in (4.1 . 1) /8 = 0.5125 moles

Now, If 1 mol of propane contains 3 moles of C

0.5125 moles of propane may contain (0.5125 . 3) / 1 = 1.5375 moles of C

Let's convert the moles to mass:

1.5375 mol . 12 g /mol = 18.45 g

5 0

2 years ago

A way of describing a chemical change that indicates what substances were present before the change and what substances are pres

musickatia [10]

Answer:

$\\ \rm\dashrightarrow Chemical\: Equation$

Explanation:

When a chemical change happens or chemical reaction happens something yields at reactants and something at products

Representing them is called chemical equation

7 0

2 years ago

Which of the following is not a organic compound, a -corn oil b -b r o m i n e c -m e t h a n e d- protein

Flura [38]

A corn oil. Because oil is treated with a solvent. After that it is refined which gets rid of free fatty acids. Finally, it is sent through steam distillation to get rid of volatile organic compounds.

6 0

3 years ago

Read 2 more answers

What is the hardest subject u ever taking, mine is chemistry

artcher [175]

Answer:

Mine is language arts brainliest?

Explanation:

7 0

2 years ago

a sample of compound determined to contain 1.71 g C and 0.287 g H. The corresponding empirical formula is

fiasKO [112]

Answer: The empirical formula is $CH_2$ .

Explanation:

Mass of C = 1.71 g

Mass of H = 0.287 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{1.71g}{12g/mole}=0.142moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.287g}{1g/mole}=0.287moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{0.142}{0.142}=1$

For H = $\frac{0.287}{0.142}=2$

The ratio of C: H = 1: 2

Hence the empirical formula is $CH_2$ .

4 0

3 years ago