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2 years ago

14

The purchase price of a camcorder is $850. What is the total price if the sales tax rate is 6.5%?

2 answers:

Gnom [1K]2 years ago

6 0

Answer:

130.77

Step-by-step explanation:

Use a calculator and do 850 divided by 6.5 which is 130.769230769 in the thousandths place round the 9 which makes u get 130.770230769. now remove 0230769 from the decimals place and 130.77 is your final answer

damaskus [11]2 years ago

5 0

Answer:

$905.25

Step-by-step explanation:

6.5% of $850 is $55.25. You add $55.25 to $850 to get the total price.

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What is the answer to 2m-6=48

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3 years ago

Which equation does the graph of the systems of equations solve? 2 linear graphs. They intersect at 1,4

Pepsi [2]

Answer:

See below.

Step-by-step explanation:

There is an infinite n umber of systems of equations that has (1, 4) as its solution. Are you given choices? Try x = 1 and y = 4 in each equation of the choices. The set of two equations that are true when those values of x and y are used is the answer.

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3 years ago

What is the volume of the prism? Enter your answer in the box as a mixed number in simplest form.

OLEGan [10]

Answer:

67.5

Step-by-step explanation:

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2 years ago

Problem 4: Solve the initial value problem

pishuonlain [190]

Separate the variables:

$y' = \dfrac{dy}{dx} = (y+1)(y-2) \implies \dfrac1{(y+1)(y-2)} \, dy = dx$

Separate the left side into partial fractions. We want coefficients a and b such that

$\dfrac1{(y+1)(y-2)} = \dfrac a{y+1} + \dfrac b{y-2}$

$\implies \dfrac1{(y+1)(y-2)} = \dfrac{a(y-2)+b(y+1)}{(y+1)(y-2)}$

$\implies 1 = a(y-2)+b(y+1)$

$\implies 1 = (a+b)y - 2a+b$

$\implies \begin{cases}a+b=0\\-2a+b=1\end{cases} \implies a = -\dfrac13 \text{ and } b = \dfrac13$

So we have

$\dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = dx$

Integrating both sides yields

$\displaystyle \int \dfrac13 \left(\dfrac1{y-2} - \dfrac1{y+1}\right) \, dy = \int dx$

$\dfrac13 \left(\ln|y-2| - \ln|y+1|\right) = x + C$

$\dfrac13 \ln\left|\dfrac{y-2}{y+1}\right| = x + C$

$\ln\left|\dfrac{y-2}{y+1}\right| = 3x + C$

$\dfrac{y-2}{y+1} = e^{3x + C}$

$\dfrac{y-2}{y+1} = Ce^{3x}$

With the initial condition y(0) = 1, we find

$\dfrac{1-2}{1+1} = Ce^{0} \implies C = -\dfrac12$

so that the particular solution is

$\boxed{\dfrac{y-2}{y+1} = -\dfrac12 e^{3x}}$

It's not too hard to solve explicitly for y; notice that

$\dfrac{y-2}{y+1} = \dfrac{(y+1)-3}{y+1} = 1-\dfrac3{y+1}$

Then

$1 - \dfrac3{y+1} = -\dfrac12 e^{3x}$

$\dfrac3{y+1} = 1 + \dfrac12 e^{3x}$

$\dfrac{y+1}3 = \dfrac1{1+\frac12 e^{3x}} = \dfrac2{2+e^{3x}}$

$y+1 = \dfrac6{2+e^{3x}}$

$y = \dfrac6{2+e^{3x}} - 1$

$\boxed{y = \dfrac{4-e^{3x}}{2+e^{3x}}}$

7 0

2 years ago

Which system of linear equations could be used to determine the price of each book

GuDViN [60]

Answer:

Let the price of the maths book be m and price of the novel book be n

Given that,

Total cost of the books is $54

The price of math book is $8 more than 3 times the price of novel book.

we get,

The system of equation as,

$\begin{gathered} m+n=54 \\ m=8+3n \end{gathered}$

Hence the system of equation to determine the price of the maths and novel book is,

$\begin{gathered} m+n=54 \\ m=8+3n \end{gathered}$

4 0

1 year ago