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2 years ago

The purchase price of a camcorder is $850. What is the total price if the sales tax rate is 6.5%?

Mathematics

2 answers:

Gnom [1K]2 years ago

6 0

Answer:

130.77

Step-by-step explanation:

Use a calculator and do 850 divided by 6.5 which is 130.769230769 in the thousandths place round the 9 which makes u get 130.770230769. now remove 0230769 from the decimals place and 130.77 is your final answer

damaskus [11]2 years ago

5 0

Answer:

$905.25

Step-by-step explanation:

6.5% of $850 is $55.25. You add $55.25 to $850 to get the total price.

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Answer the following: GCF of 20 & 32 GCF of 45 & 75

Jet001 [13]

Answer:

GCF OF 20 AND 32: 4

Gcf of 45 and 75: 15

Step-by-step explanation:

GcF of 20 and 32

Factors of 20: 1, 2, 4, 5, 10, 20

Factors of 32: 1, 2, 4, 8, 16, 32

COMMON FACTORS: 1, 2, 4

GCF:4

Gcf of 45 and 75

Factors of 45: 15, 9, 5, 3, 1.

Factors of 75: 25, 15, 5, 3, 1.

CommoN factors: 1, 3, 5, 15

GCF:15

HOPE OT HELPED

3 0

3 years ago

Read 2 more answers

Please help!! Find the zeros and vertex of the parabola

Sergeeva-Olga [200]

Answer:

Vertex: (1/2, 16)

Zeros: t = − 1 /2, 3/2

Step-by-step explanation:

4 0

2 years ago

Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

5 0

2 years ago

An ice cream cone is filled with vanilla and chocolate ice cream at a ratio of 2:1. If the diameter of the cone is 2 inches and

Sophie [7]

Volume of cone=(1/3)hpir^2

d/2=r
d=2
d/2=2/2=1=r
h=6

V=(1/3)6pi1^2
V=2pi in^3 is volume

ratio of 2:1

2+1=3
2pi=3 units
divide both sides by 3
2/3pi=1 unit

vanila=2 units
times 2/3pi by 2
4/3pi
aprox pi=3.141592
4.188
round
4.2 in^3 of vanilla

3 0

3 years ago

Read 2 more answers

$84 increased by 120 percent

Elanso [62]

$\rm 84+120\% \\ \\ 84+ \frac{12\not0\cdot84}{10\not0}= \\ \\ 84+ \frac{1008}{10}= \\ \\ 84+100,8=\\ \\ \bold{184,8\$}$

5 0

2 years ago