Answer:
The heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.
Let X = <u><em>weights of the fruits</em></u>
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean weight = 733 grams
= standard deviation = 9 grams
Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;
P(X > x) = 0.05 {where x is the required weight}
P(
>
) = 0.05
P(Z >
) = 0.05
In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;



x = 747.81 grams
Hence, the heaviest 5% of fruits weigh more than 747.81 grams.
Like I said on the other question. Slope will ALWAYS be the number beside x and y-intercept will always be after that.
Slope-intercept form = y = mx + b
Slope goes where m is and y-intercept goes where b is.
Hope this helps!
Answer:
112
Step-by-step explanation:
correct me if im wrong.
I got this from doing 30 percent out of 160
160×0.30
160-48=112
Answer:
P(Spinner lands on purple section) = 0.6 = 60%
Step-by-step explanation:
We are given the following in the question:
Number of sections = 10
Number of purple sections = 6
a) probability that the spinner will land on purple purple
P(purple) =

0.6 is the probability that the spinner will land on purple purple.
b) Interpretation of probability

There is a 60% chance that the spinner will land on purple color.