Answer:
15?
maybe
Step-by-step explanation:
Answer:
The best choice would be hiring a random employee from company A
Step-by-step explanation:
<em>Supposing that the performance rating of employees follow approximately a normal distribution on both companies</em>, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.
In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings
The z-value corresponding to company A is

where
= mean of company A
= 5.5 (average of rating between 1 and 10)
s = standard deviation of company A

We do the same for company C

This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.
So, the best choice would be hiring a random employee from company A
Answer:
R
H
S
= cos
2
x
Step-by-step explanation:
Step-by-step explanation:
We apply the pythagorean theorem on ABC.
AC^2=11^2+60^2 = 3600 + 121 = 3721
AC=61
Which means that sin(BAC) = 60/61.
However, sin^2(BAC) + cos^2(BAC)=1.
3600/3721 + cos^2(BAC) = 3721/3721.
cos^2(BAC) = 121/3721.
BAC is an acute angle so the cos is a positve number.
cos(BAC) = 11/61.
Lastly, x/60 = cos(BAC), so x= 660/61
80 dollars, this is because he has lost ten pounds and he is given 8 dollars per pound. This makes the equation 10x8 and that equals 80. Hope this helps!