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3 years ago

I need help with this please :)

Mathematics

1 answer:

denpristay [2]3 years ago

7 0

Answer:

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Step-by-step explanation:

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A woman standing on a hill sees a flagpole that she knows is 40 ft tall. the angle of depression to the bottom of the pole is 14

NemiM [27]

Let distance form the pole = x and height of the hill = y ft

now we can set up 2 equayions
tan 18 = (40-y)/x
tan 14 = y/x

from second equation y = sxtan14 so we have:-
tan 18 = ( 40 - x tan 14) / x

x tan 18 = 40 - x tan 14
x(tan 18 + tan 14) = 40

x = 40 / (tan18 + tan 14) = 69.66 feet Answer

6 0

3 years ago

If x = (√2 + 1)^-1/3 then the value of x^3 + 1/x^3 is

Shtirlitz [24]

Step-by-step explanation:

Given: x = {√(2) + 1}^(-1/3)

Asked: x³+(1/x³) = ?

Solution:

We have, x = {√(2) + 1}^(-1/3)

⇛x = [1/{√(2) + 1}^(1/3)]

[since, (a⁻ⁿ = 1/aⁿ)]

Cubing on both sides, then

⇛(x)³ = [1{/√(2) + 1}^(1/3)]³

⇛(x)³ = [(1)³/{√(2) + 1}^(1/3 *3)]

⇛(x)³ = [(1)³/{√(2) + 1}^(1*3/3)]

⇛(x)³ = [(1)³/{√(2) + 1}^(3/3)]

⇛(x * x * x) = [(1*1*1)/{√(2) + 1)^1]

⇛x³ = [1/{√(2) + 1}]

Here, we see that on RHS, the denominator is √(2)+1. We know that the rationalising factor of √(a)+b = √(a)-b. Therefore, the rationalising factor of √(2)+1 = √(2) - 1. On rationalising the denominator them

⇛x³ = [1/{√(2) + 1}] * [{√(2) - 1}/{√(2) - 1}]

⇛x³ = [1{√(2) + 1}/{√(2) + 1}{√(2) - 1}]

Multiply the numerator with number outside of the bracket with numbers on the bracket.

⇛x³ = [{√(2) + 1}/{√(2) + 1}{√(2) - 1}]

Now, Comparing the denominator on RHS with (a+b)(a-b), we get

a = √2
b = 1

Using identity (a+b)(a-b) = a² - b², we get

⇛x³ = [{√(2) - 1}/{√(2)² - (1)²}]

⇛x³ = [{√(2) - 1}/{√(2*2) - (1*1)}]

⇛x³ = [{√(2) - 1}/(2-1)]

⇛x³ = [{√(2) - 1}/1]

Therefore, x³ = √(2) - 1 → → →Eqn(1)

Now, 1/x³ = [1/{√(2) - 1]

⇛1/x³ = [1/{√(2) - 1] * [{√(2) + 1}/{√(2) + 1}]

⇛1/x³ = [1{√(2) + 1}/{√(2) - 1}{√(2) + 1}]

⇛1/x³ = {√(2) + 1}/[{√(2) - 1}{√(2) + 1}]

⇛1/x³ = [{√(2) + 1}/{√(2)² - (1)²}]

⇛1/x³ = [{√(2) + 1}/{√(2*2) - (1*1)}]

⇛1/x³ = [{√(2) + 1}/(2-1)]

⇛1/x³ = [{√(2) + 1}/1]

Therefore, 1/x³ = √(2) + 1 → → →Eqn(2)

On adding equation (1) and equation (2), we get

x³ + (1/x³) = √(2) -1 + √(2) + 1

Cancel out -1 and 1 on RHS.

⇛x³ + (1/x³) = √(2) + √(2)

⇛x³ + (1/x³) = 2

Therefore, x³ + (1/x³) = 2

Answer: Hence, the required value of x³ + (1/x³) is 2.

Please let me know if you have any other questions.

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3 years ago

Alice has $90 to spend on

nlexa [21]

Answer:

step by step explanation:

if she gets $10 off of her purchase that means she would have a little extra money to another shirt

5 0

3 years ago

What is the percent of decrease from 100 to 49? Write your answer using a percent sign (%).

slavikrds [6]

Answer:

Step-by-step explanation:

Decrease = 100 - 49 = 51

Percentage of decrease =

$=\frac{51}{100}*100$

= 51%

6 0

3 years ago

Write a conditional statement. Write the converse, inverse and contrapositive for your statement and determine the truth value o

photoshop1234 [79]

A conditional statement involves 2 propositions, p and q. The conditional statement, is a proposition which we write as: p⇒q,

and read "if p then q"

Let p be the proposition: Triangle ABC is a right triangle with m(C)=90°.

Let q be the proposition: The sides of triangle ABC are such that

$|AB|^2=|BC|^2+|AC|^2$ .

An example of a conditional statement is : p⇒q, that is:

if Triangle ABC is a right triangle with m(C)=90° then The sides of triangle ABC are such that $|AB|^2=|BC|^2+|AC|^2$

This compound proposition (compound because we formed it using 2 other propositions) is true. So the truth value is True,

the converse, inverse and contrapositive of p⇒q are defined as follows:

converse: q⇒p
inverse: ¬p⇒¬q (if [not p] then [not q])
contrapositive: ¬q⇒¬p

Converse of our statement:

if The sides of triangle ABC are such that $|AB|^2=|BC|^2+|AC|^2$
then Triangle ABC is a right triangle with m(C)=90°

True

Inverse of the statement:

if Triangle ABC is not a right triangle with m(C) not =90° then The sides of triangle ABC are not such that $|AB|^2=|BC|^2+|AC|^2$

True

Contrapositive statement:

if The sides of triangle ABC are not such that $|AB|^2=|BC|^2+|AC|^2$ then Triangle ABC is not a right triangle with m(C)=90°

True

4 0

4 years ago