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mash [69]
3 years ago
12

Given square ABCD. Two isosceles triangles ABP and BCQ are constructed with bases

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

I'm gonna guess 17? Don't take my advice i'm not sure.

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Can someone help me with this! It would be much appreciated!!
love history [14]

Answer:

1. parallelogram

2. trapezoid

3.rectangle

4. parallelogram

5. trapezoid

6. rhombus

7.rectangle

8. rhombus

3 0
3 years ago
If the circumference is 31.4, what are the radius and the area?
jekas [21]

Answer:

radius = 5 units

area of a circle = 15.7units²

Step-by-step explanation:

given that the circumference of a circle = 31.4

radius = ?

recall that the formulae for finding the circumference of a circle  =  2πr

circumference of a circle  = 2 x 3.14 x r

31. 4 = 6.28r

divide both sides by the coefficient of r which is 6.28

31.4/6.28 = 6.28r/6.28

5 = r

radius = 5 units

therefore the radius of the circle whose circumference is 31.4 units is evaluated to be 5units

to find the area of the circle

recall the formula = πr²

area of a circle = 3.14 x 5²

area of a circle = 3.14 x 25

area of a circle = 15.7units²

7 0
3 years ago
5y + 4(-5 + 3y) = 1 – y solve step by step please
Studentka2010 [4]
Step by step, meaning explaining the equation right and answer?
3 0
3 years ago
Read 2 more answers
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
yanalaym [24]

Answer:

I am not sure .but i will try

i think so i will give correct answer

perpendicular of triangle is 22-10 cm =12 cm bcz both sides of triangle are equal =22

area of rectangle l×w= 22×17=374

area of triangle =h×b/2 Now we r not having h

lets find it

use pythagorus theorum (h2=P2+b2....2 here is square)

h=22.5cm

22.5×19=427(area of triangle )

374+427=801cm sq

i tried my best dont know its righr of wrong

pls mark me as brainlieast

3 0
3 years ago
What are the x intercepts of the quadratic function? Y=-x^2+2x-1
saw5 [17]

Answer:

x = 1

Step-by-step explanation:

Given in the question the equation

y = -x² + 2x - 1

To find the x-intercept, substitute in 0 for y

0 = -x² + 2x - 1

To find value of x use quadratic equation

x = -b ± √b²-4ac / 2a

  here a = -1

           b = 2

           c = -1

x1 = -2 + √2²-4(-1)(-1) / 2(-1)

   = -2 + 0 / -2

   = -2 / -2

   = 1

x2 = -2 - √2²-4(-1)(-1) / 2(-1)

   = -2 - 0 / -2

   = -2 / -2

   = 1

8 0
3 years ago
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