If we know that two sets of corresponding angles and the corresponding included sides are congruent in two triangles, what can we say about the triangles?
Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
The equation of an ellipse is x²/a² + y²/b² =1
a being the distance between the center & x intercept =7
b being the distance between the center & y intercept =5
Hence the equation of this ellipse is:
x²/49 + y²/25 =1
