5. What type of quadrilateral is DEFG? A square B rhombus trapezoid D parallelogram

A model rocket is launched with an initial upward velocity of 60 m/s. The rocket's height h (in meters) after t seconds is given

Vedmedyk [2.9K]

Answer:

0.47 and 11.53

Step-by-step explanation:

h = 60t − 5t²

27 = 60t − 5t²

5t² − 60t + 27 = 0

Quadratic formula:

x = [ -b ± √(b² − 4ac) ] / 2a

t = [ -(-60) ± √((-60)² − 4(5)(27)) ] / 2(5)

t = (60 ± √3060) / 10

t = 0.47 or 11.53

3 0

3 years ago

Rank these graphs on the basis of the angular acceleration of the object. Rank positive angular accelerations as larger than neg

insens350 [35]

The ratio of change in angular position to change in time is defined as the angular velocity. Thus, the slope of an angular position versus time graph gives the angular velocity of the object being graphed.
The rank of the given graphs can be written as follow,positive graphs are listed first.
The line B is the line with the greater positive slope.
The line B is the line with positive slope but is less than the slope of line B.
The lines A,t ,and F are the lines with the zero slope.
The lines D and E are parallel to each other and have same negative slope.

7 0

3 years ago

Compare the functions shown below:

emmasim [6.3K]

The intersection with the y axis occurs when x = 0.
We have then:

For f (x):
$f (0) = -3 (0) - 5

f (0) = 0 - 5

f (0) = - 5$

For g (x):
We can observe in the graph that when x = 0, the value of the function cuts to the y axis in y = -3

For h (x):
$h (0) = 2cos (2 (0) -\pi) +4

h (0) = 2cos (0-\pi) +4

h (0) = 2cos (-\pi) +4$
$h (0) = 2 (-1) +4

h (0) = -2 + 4

h (0) = 2$

Therefore, the graph with the intersection with the largest y axis is h (x)

Answer:
the greatest y-intercept is for:
C. h(x)

6 0

3 years ago

Which of the following is the equation 6^4 = 1,296 written in logarithmic form?

masya89 [10]

Given $6^4 = 1,296$

To write in logarithmic form we convert exponential form to logarithmic form

We apply the following rule

$b^x = a$ can be written as $log_b(a) = x$

here b = 6 , x=4 and a = 1296

$6^4 = 1,296$ can be written as $log_6(1,296) = 4$

option A is correct

8 0

3 years ago

Read 2 more answers

How many 6 digit different locker combinations are possible if no repeat numbers are allowed?

Alex_Xolod [135]

Since we are trying to find the number of sequences can be made without repetition, we are going to use a combination.

The formula for combinations is:

$_n C _k = \dfrac{n!}{k! (n - k)!}$

$n$ is the total number of elements in the set
$k$ is the number of those elements you are desiring

Since there are 10 total digits, $n = 10$ in this scenario. Since we are choosing 6 digits of the 10 for our sequence, $k = 6$ in this scenario. Thus, we are trying to find $_{10} C _6$ . This can be found as shown:

$_{10} C _6 = \dfrac{10!}{6! \cdot 4!} = \dfrac{10 \cdot 9 \cdot 8 \cdot 7}{4!} = \dfrac{5040}{24} = 210$

There are 210 total combinations.

7 0

3 years ago