Answer:
x=1
y=s
z=1
Step-by-step explanation:
(x, y, z)=(1, 0, 1)
Substitute 0 for y
Confirming if t=0 satisfy the other equation
x = e^−2t cos 4t = e^−2(0)cos(4*0)
= e^(0)cos(0) = 1
z = e^−2t = e^−2(0) = 0
Therefore t=0 satisfies the other equation
Finding the tangent vector at t=0
The vector equation of the tangent line is
(1, 0, 1) +s(0,1,0)= (1, s, 1)
The parametric equations are:
x=1
y=s
z=1
The Answer is A
Explanation:
The standard form equation for an ellipse is:
(x - h)² / a² + (y - k)² / b² = 1
So looking at the picture above you can see that the center of the ellipse is at the origin which is (0;0) making both h and k zero.
It is then observed that the x-intercepts are at 12 meaning a=12 and y- intercepts are at approximately square root of 95 which is 9.746... which are 'k'
So you can conclude by saying that:
x²/12² + y²/(sqrt of 95)² = 1
then giving you the answer of A which is:
x²/144 + y²/95 = 1
FOIL this out. 3x*x = 3x^2; 3x*8= 24x; -8*x = -8x; -8*8=-64. Combine like terms to get