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notsponge [240]
3 years ago
8

If you invest $1000 at an interest rate of 2.5% compounded continuously, calculate how many years. How long will it take for you

r investment to double?
Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

It will take about 27.7 years

Step-by-step explanation:

* Lets talk about the compound continuous interest

- Compound continuous interest can be calculated using the formula:  

 A = P e^rt  

• A = the future value of the investment, including interest

• P = the principal investment amount (the initial amount)

• r = the interest rate  

• t = the time the money is invested for

- The formula gives you the future value of an investment,  

  which is compound continuous interest plus the  principal.  

- If you want to calculate the compound interest only, you need

 to deduct the principal from the result.  

- So, your formula is:

 Compounded interest only = Pe^(rt)  - P

* Now lets solve the problem

∵ The invest is $ 1000

∴ P = 1000

∵ The interest rate is 2.5%

∴ r = 2.5/100 = 0.025

- They ask about how long will it take to make double the investment

∴ A = 2 × 1000 = 2000

∵ A = P e^(rt)

∴ 2000 = 1000 (e)^(0.025t) ⇒ divide both sides by 1000

∴ 2000/1000 = e^(0.025t)

∴ 2 = e^(0.025) ⇒ take ln for both sides

∴ ln(2) = ln[e^(0.025t)]

∵ ln(e)^n = n

∴ ln(2) = 0.025t ⇒ divide both sides by 0.025

∴ t = ln(2)/0.025 = 27.7 years

* It will take about 27.7 years

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<u>Step 1: Add the numbers: 9.5 +6.2 = 15.7</u>

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<u />

- To solve this equation, the first step is to add the numbers 9.5 + 6.2 into the equation and it will lead to 15.7 as the number for step one.

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- To solve this equation, the third step is to multiply the numbers 8.6 x 3.45 into the equation and it will lead 29.67 as the final answer for the whole equation.

Answer:      

=29.67

 

Hope this helps.

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