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iren [92.7K]
3 years ago
9

name two physical properties that could be used to distinguish between the material in each pair 1,cork and lead 2,copper and si

lver 3,water and benzene 4,sulphur and iron?​
Chemistry
1 answer:
kozerog [31]3 years ago
6 0

The physical properties of each material can be used to tell each apart. One example of these properties is their respective densities and polarities, among others.

In the case of Cork and Lead, we can name differences such as:

  1. Densities, since lead has a very high density when compared to the low density of cork
  2. Colors, given that lead is a blueish silver color and cork is not.
  3. Melting points are another way to tell them apart since lead melts at 330 degrees while cork begins to melt at 200.

As for copper and silver, though not identical in numbers, both elements share a wide range of properties. One physical property to be used when telling them apart is color, as silver has its own aptly named color whilst copper shines in a bright brown-red coloration.

As opposed to the previous group, benzene and water can often be physically identical. However, this does not mean that they share all physical properties. One example of this and a property that can tell them apart is their polarity, given that water is highly polar and benzene is not polar at all.

Of the groups listed, the grouping of sulfur and iron is the easiest to differentiate given that they possess distinct:

  • Color
  • Melting points
  • Boiling points
  • Odors
  • Conductivities

and so on.

These are some properties that are different between each grouped elements and can be used by scientists or students to differentiate the substances from one another.

To learn more visit:

brainly.com/question/18327661?referrer=searchResults

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You need a 35% alcohol solution. on hand, you have a 405 ml of a 30% alcohol mixture. you also have 80% alcohol mixture. how muc
Bumek [7]

You must add 45 mL of the 80 % alcohol to the 30 % alcohol to get a 35 % solution.

You can use a modified dilution formula to calculate the volume of 80 % alcohol

V1×C1 + V2×C2 = V3×C3

Let the volume of 80 % mixture 1 = <em>x</em> mL. Then the volume of the final 35 % mixture 3 = (405 + <em>x</em> ) mL

(<em>x</em> mL×80 % alc) + (405 mL×30 % alc) = (405 + <em>x</em>)mL × 35 % alc

80x + 12 150 = 14 175 + 35 x

45x = 2025

x = 2025/45 = 45

4 0
3 years ago
Need help fast!!
stepan [7]

Answer:

The answer is "5.18 ".

Explanation:

It's a question of chemistry. Therefore, the following solution is provided:

We will first determine the solution's pOH. The following can possible:

The concentration of Hydroxide ion [OH^{-}] = 1.5\times 10^{-9}\ M

pOH =?\\\\pOH = -\log [OH^{-}]\\\\pOH = -\log 1.5\times 10^{-9}\\\\pOH = 8.82\\\\

Furthermore, the pH of the solution shall be established. It was provided as follows:

pOH = 8.82\\\\pH =?\\\\pH + pOH = 14\\\\pH + 8.82 = 14\\\\

When collecting all the like terms:

pH = 14 -8.82\\\\pH = 5.18

Therefore, the solution of pH is 5.18.

8 0
3 years ago
At which point does the roller coaster have very little kinetic energy and very little potential energy ?
Nana76 [90]
When it would be on a flat area with no slope. and no movement
6 0
4 years ago
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zhenek [66]

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7 0
3 years ago
4. Solve the following heat flow problem, being sure to show all your work (you may either type your
Viktor [21]

Answer:

0.70 J/g.°C

Explanation:

Step 1: Given data

  • Mass of graphite (m): 402 g
  • Heat absorbed (Q): 1136 J
  • Initial temperature: 26°C
  • Final temperature: 30 °C
  • Specific heat of graphite (c): ?

Step 2: Calculate the specific heat of graphite

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 1136 J / 402 g × (30°C - 26°C)

c = 0.70 J/g.°C

5 0
4 years ago
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