for a theoretical yield of 22 g and actual yield of 13 g, calculate the percent yield for a chemical reaction

ale4655 [162]

Answer:

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7 0

3 years ago

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How many grams of H2O will be produced if 750. grams of Fe are produced?

aleksandr82 [10.1K]

Answer:

$\boxed{\small \sf \: Mass \: of \: H_2O =322.2 \: grams}$

Explanation:

Given:

Mass of ferous (Fe) produced = 750 gram.

To find:

Mass of water produced= ?

Solution:

Molar mass of Fe is 55.84 gram/mol

Let's find out the number of moles of ferous produced.

$\small \sf Number \: of \: moles = \frac{Given \: mass \: of \: substance }{Molar \: mass \: of \: substance}$

Substituting the given data in above formula.

$\small \sf Number \: of \: moles = \frac{750}{55.84}$

$\boxed{\small \sf Number \: of \: moles \: of \: Fe= 13.43 \: moles}$

Now the given reaction is,

$Fe_3O_4 + 4H_2 \rightarrow 3Fe + 4H_2O$

For every 3 mole of production of Fe, 4 mole of waters are produced.
let for 13.43 moles of Fe x moles of H2O will be produced.

now calculate the number of moles of H2O

$\sf \: \frac{3}{4} = \frac{13.43}{x} \\ \sf x = \frac{13.43 \times 4}{3} \\ \sf x = 17.90 \: moles$

$\small \boxed{\sf number \: of \: moles \: of \: H_2O= 17.90 \: moles}$

mass of one mole of H2O is 18 gram, so we can calculate mass of 17.90 moles.

$\small \sf \: Mass \: of \: H_2O = 17.90 \times 18 \\ \boxed{\small \sf \: Mass \: of \: H_2O =322.2 \: grams}$

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3 0

2 years ago

Which statement describes a property of covalent compounds? They have a high boiling point because of strong intermolecular forc

svet-max [94.6K]

The correct answer is:

They have a low boiling point because of weak intermolecular forces.

3 0

3 years ago

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cho các chất sau NaO2,Na,NaOH,Na2SO4,Na2SO3,NaCl,AgCl hãy lập thành dãy chuyển hoá , hoàn thành bằng phương tình phản ứng

Archy [21]

Answer:

brainless me plss i help you out

5 0

3 years ago

Calculate the volume in liters of a M barium chloride solution that contains of barium chloride . Round your answer to significa

Reptile [31]

Answer:

1.667L of a 0.30M BaCl₂ solution

Explanation:

Of a 0.30M barium chloride, contains 500.0mmol of barium chloride.

Molarity is an unit of concentration used in chemistry defined as the moles of solute present in 1 liter of solution.

In a 0.30M BaCl₂ solution there are 0.30 moles of BaCl₂ in 1 liter of solution.

Now, in your solution you have 500mmol of BaCl₂ = 0.500 moles of BaCl₂ (1000 mmol = 1 mol). Thus, 0.500 moles of BaCl₂ are present in:

0.500 moles * (1L / 0.30 moles) =

<h3>1.667L of a 0.30M BaCl₂ solution</h3>

5 0

3 years ago