for a theoretical yield of 22 g and actual yield of 13 g, calculate the percent yield for a chemical reaction
1 answer:
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Answer:
613 mg
Explanation:
Number of fargday's
Here, I = 9.20 A
t = 10.5 min
= 10.5 x 60 seconds
So,
= 0.0208 F
Here, 2e, 2F
2F = 1 mol of Ni
1 mol = 59 gm of Ni
0.0104 mol = 59 x0.0104 gm Ni
= 0.613 gm Ni
= (0.613 x 1000 ) mg of Ni
= 613 mg of Ni