All categories

3 years ago

15% of $70 get it correct for a 100 I need proof first

Mathematics

2 answers:

Evgen [1.6K]3 years ago

8 0

15% of $70 =$10.5.

You would do
15x70=1050
1050/100 because a percent is always equal to 100
1050/100=10.5

lana [24]3 years ago

5 0

Answer: 170% da da

Step-by-step explanation:

You might be interested in

The sum of the least and greatest of three consecutive integers is 50. What is the middle integer?

suter [353]

x + (x + 2) = 50

Combine like terms.

2x + 2 = 50

Subtract 2 from both sides.

2x = 48

Divide both sides by 2.

x = 24

Now that we have the value of x, we can find the value of the 2nd integer by adding 1 to the value of x.

24 + 1 = 25

<h3>The middle integer is equal to 25.</h3>

3 0

3 years ago

Select the three expressions that are equivalent to 6^{2}6 2 6, squared. a: (6^9/6^8)^2 b: 6 times 6 times 6 times 6 times 6 tim

Kamila [148]

Question:

Select the three expressions that are equivalent to $6^2$ :

a: $(\frac{6^9}{6^8})^2$

b: $\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }$

c: $\frac{6^4}{6^2}$

d: $\frac{6^5 * 6^7}{6^{10}}$

Answer:

a: $(\frac{6^9}{6^8})^2$

c: $\frac{6^4}{6^2}$

d: $\frac{6^5 * 6^7}{6^{10}}$

Step-by-step explanation:

Given

$6^2$ :

Required

Find equivalent expressions

<em>To solve this question; we'll simplify options a to do, one after the other</em>

a: $(\frac{6^9}{6^8})^2$

From laws of indices;

$\frac{a^m}{a^n} = a^{m-n}$

This implies that;

$(\frac{6^9}{6^8})^2 = (6^{9-8})^2$

$(\frac{6^9}{6^8})^2 = (6^{1})^2$

From laws of indices;

${a^m}^n = a^{m*n} = a^{mn}$

This implies that

$(\frac{6^9}{6^8})^2 = (6^{1*2})$

$(\frac{6^9}{6^8})^2 = 6^{2}$

Hence, $(\frac{6^9}{6^8})^2$ is equivalent to $6^2$

b. $\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }$

From laws of indices;

$a^m * a^n = a^{m+n}$

This implies that

$\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{1+1+1+1+1+1}}{6^{1+1+1}}$

$\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = \frac{6^{6}}{6^{3}}$

From laws of indices;

$\frac{a^m}{a^n} = a^{m-n}$

This implies that

$\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{6-3}$

$\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 } = 6^{3}$

Hence; $\frac{6 * 6 * 6 * 6 * 6 * 6 * 6}{6 * 6 * 6 }$ is not equivalent to $6^2$

c. $\frac{6^4}{6^2}$

From laws of indices;

$\frac{a^m}{a^n} = a^{m-n}$

This implies that

$\frac{6^4}{6^2} = 6^{4-2}$

$\frac{6^4}{6^2} = 6^{2}$

Hence, $\frac{6^4}{6^2}$ is equivalent to $6^2$

d. $\frac{6^5 * 6^7}{6^{10}}$

From laws of indices;

$a^m * a^n = a^{m+n}$

This implies that

$\frac{6^5 * 6^7}{6^{10}} = \frac{6^{5+7}}{6^{10}}$

From laws of indices;

$\frac{a^m}{a^n} = a^{m-n}$

This implies that

$\frac{6^5 * 6^7}{6^{10}} = 6^{5+7-10}$

$\frac{6^5 * 6^7}{6^{10}} = 6^{2}$

Hence, $\frac{6^5 * 6^7}{6^{10}}$ is equivalent to $6^2$

3 0

3 years ago

Read 2 more answers

Simplify 3x - 4 - 5x = 6 + 4x + 2

AfilCa [17]

Answer:

x=-2

Step-by-step explanation:

-2x-4=8+4x

-6x=8+4

-6x=12

divide both side by -6

x=-2

8 0

3 years ago

16 2/3- 4 3/4 equals ?

Greeley [361]

16 2/3
- 4 3/4

First: Find a common denominator (LCD) for the fractions. In this case, 12.

16 8/12
- 4 9/12

11 11/12

3 0

3 years ago

Question

Vlad1618 [11]

Answer:

-9, or A

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers