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Aloiza [94]
3 years ago
13

What happens as a result of an increase in the intensity of a sound wave?

Physics
2 answers:
larisa [96]3 years ago
8 0

As the intensity increases the energy increases.

Answer:

C. the energy of the sound wave increases

Bogdan [553]3 years ago
8 0
C. The energy of the sound wave increases
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Imagine a car moving at a speed of 10 m/s it starts speeding up at an acceleration of 2 m/s/s. What will the car's speed be afte
alexandr402 [8]

Answer:

14 m/s

18 m/s

22 m/s

Explanation:

The car is moving at constant acceleration, so we can find its velocity at time t using the equation:

v=u+at

where

u = 10 m/s is the initial velocity

a=2 m/s^2 is the  acceleration

t is the time

Substituting the different times, we find:

At t = 2 s:

v=10+(2)(2)=14 m/s

At t = 4 s:

v=10+2(4)=18 m/s

At t = 6 s:

v=10+2(6)=22 m/s

6 0
3 years ago
What are the advantages of division of labor and the disadvantages of division of labor<br>​
Andrei [34K]

Answer:

Advantage:

It makes work faster and easier

Disadvantage:

The work to its very best

Explanation:

More people reduces the time spent on one work which makes easier to finish but the work might not be done to its very best because different people are doing the job

7 0
4 years ago
Please help fast!!
daser333 [38]

The answer is C..........      

4 0
3 years ago
A deer is running from a mountain lion when it encounters a fence that is 1.50 m high. Seeing the fence, the deer jumps, leaving
Novosadov [1.4K]

Answer:

Explanation:

Given

Initial Velocity (u)=13 m/s

angle=29^{\circ}

distance between fence and deer=2.5 m

We consider deer jump similar to projectile motion

equation of trajectory

y=xtan\theta -\frac{gx^2}{2u^2(cos\theta )^2}

y=2.5tan(29)-\frac{9.8\times 2.5^2}{2\times 13^2\times (cos29)^2}

y=1.385-0.2368=1.148 m

Thus deer will cross the fence with an difference in its jump and fence

1.5-1.148=0.351 m

h_{max}=\frac{u^2sin^2\theta }{2g}

h_{max}=\frac{13^2\times (sin29)^2}{2\times 9.8}

h_{max}=2.02 m

so deer rises during when it is over fence

8 0
4 years ago
It takes 6 seconds for a stone to fall to the bottom of a mine shaft. how deep is the shaft
Margaret [11]
You need the kinematic equation for distance as a function of acceleration:

d = [v(initial) *t] + 0.5a*t^{2}

where a = gravitational acceleration 9.8m/s^{2}
v(initial) = starting velocity
t = time of fall

if the stone started at rest then v(initial) = 0 making the equation simply 0.5a * t^{2}

Let me know if you still need further help :)
6 0
3 years ago
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