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Kisachek [45]
3 years ago
7

Please help fast!!

Physics
1 answer:
daser333 [38]3 years ago
4 0

The answer is C..........      

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Question 2 (1 point)
Vesna [10]

Answer:

400m

Explanation:

use formula

velocity = displacement /time

8 0
3 years ago
A variable that is changed by the researcher is called ___
soldier1979 [14.2K]
An independent variable :)) hope I helped
5 0
3 years ago
Terms used to measure motion
pychu [463]

Answer:

velocity term

Explanation:

7 0
3 years ago
Read 2 more answers
To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeof
BlackZzzverrR [31]
<h2>Answer: 26,8 s</h2>

Explanation:

If we are talking about an acceleration at a constant rate , we are dealing with constant acceleration, hence we can use the following equations:

{V_{f}}^{2}={V_{o}}^{2}+2ad (1)

V_{f}=V_{o}+at (2)

Where:

V_{f} is the final velocity of the plane (the takeoff velocity in this case)

V_{o}=0 is the initial velocity of the plane (we know it is zero because it starts from rest)

a=5m/s^{2} is the constant acceleration of the plane to reach the takeoff velocity

d=1800m is the distance of the runway

t is the time

Knowing this, let's begin with (1):

{V_{f}}^{2}=0+2(5m/s^{2})(1800m) (3)

{V_{f}}^{2}=18000m^{2}/s^{2} (4)

V_{f}=134.164 m/s (5)

Substituting (5) in (2):

134.164 m/s=0+(5m/s^{2})t (6)

Finding t:

t=26.8 s This is the time needed to take off

6 0
3 years ago
How long is the racetrack if it takes a racecar 3.4 s travelling at 75 m/s to finish?​
RSB [31]

Answer:

255 metres

Explanation:

The answer to thi question is actually quite simple. Since the car goes for 3.4 seconds, and it goes 75 metres every second, the answer is just 3.4 multiplied by 75 Metres.

5 0
3 years ago
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