I love math but math hates me
Answer:
(x - 2)^2 + (y + 5)^2 = 5
Step-by-step explanation:
If the center is at (h, k) : (2, -5), then the general form of the equation of this circle is
(x - 2)^2 + (y + 5)^2 = r^2, and we must find r^2.
We know that (3, -3) is a point on the circle. Substitute 3 for x and -3 for y in the above equation to find r^2:
(3 - 2)^2 + (-3 + 5)^2 = r^2, or
1^2 + 2^2 = r^2
Then r^2 = 5, and the desired equation is
(x - 2)^2 + (y + 5)^2 = 5 or (√5)^2
At (x,y)=(0,-1)
-10x + 4y = -10(0) + 4(-1) = -4
Does that make the statement true? Is -4 ≥ -4? It's equal, so yes.
Answer: YES